We are given that the slope of the line is $m = 3$ and the point $(3, 1)$ lies on the line. The equation of the line is expressed in the form $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept.

We will use the point-slope form of a line to find $b$. This form is:

$y = mx + b$

Substitute the given point $(x, y) = (3, 1)$ and $m = 3$ into the equation:

$1 = 3(3) + b$

Simplify the right-hand side:

$1 = 9 + b$

Now, solve for $b$:

$b = 1 - 9 = -8$

So, the equation of the line is:

$y = 3x - 8$

Let me know if you need more details or explanations!

Here are 5 related questions:

1. How do you find the slope given two points on a line?
2. How do you determine if a point lies on a given line?
3. What is the point-slope form of a line and when do you use it?
4. How does changing the slope affect the steepness of a line?
5. What happens to a line if you change only the y-intercept?

Tip: The y-intercept is where the line crosses the y-axis (when $x = 0$).