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The problem asks to find the equation of the straight line \( QR \) given points \( Q \) and \( R \) in the diagram.

Here is the process to find the equation of line \( QR \):

1. **Determine the coordinates of points \( Q \) and \( R \):**
   - Point \( R \) is given as \( (-7, 4) \).
   - For point \( Q \), let's assume we calculate it from the diagram (it appears near \( P(3, 7) \)), but we need to estimate based on the symmetry of the parallelogram and additional information if available.

2. **Find the slope (gradient) of line \( QR \):**
   The slope of a line through two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is calculated by the formula:
   \[
   m = \frac{y_2 - y_1}{x_2 - x_1}
   \]
   Using coordinates \( Q(x_Q, y_Q) \) and \( R(-7, 4) \).

3. **Equation of the line:**
   Once the slope \( m \) is determined, the equation of the line can be written in the point-slope form:
   \[
   y - y_1 = m(x - x_1)
   \]
   Substituting \( m \) and one of the points (either \( Q \) or \( R \)) into this equation will yield the equation of the line \( QR \).

Would you like help estimating point \( Q \) or any further steps in the process?

Find the equation of the straight line QR, given points Q and R from the diagram of a parallelogram on a Cartesian plane.

Learn how to find the equation of the line QR in a parallelogram on a Cartesian plane. This problem explores key concepts in coordinate geometry, such as calculating the slope and forming the linear equation using point-slope form. Suitable for students in Grades 9-11.

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