Math Problem Statement

The equation of the circle drawn above is :

The equation of the circle drawn above is:

Solution

To find the equation of the circle in the given graph, we need to determine two things:

  1. The center of the circle (h,k)(h, k)
  2. The radius rr

From the image:

  • The center of the circle appears to be at the origin (0,0)(0, 0).
  • The radius can be determined by counting the number of grid units from the center to the boundary of the circle. It looks like the radius is 6 units (from (0,0)(0,0) to (6,0)(6, 0), (0,6)(0, 6), etc.).

Standard equation of a circle:

(xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2 Where (h,k)(h, k) is the center and rr is the radius.

Since the center is (0,0)(0, 0) and the radius is 6, the equation becomes: x2+y2=62x^2 + y^2 = 6^2 x2+y2=36x^2 + y^2 = 36

Thus, the equation of the circle is: x2+y2=36x^2 + y^2 = 36

Would you like further explanation or details?

Here are some related questions to consider:

  1. What is the general form of the equation of a circle with a different center?
  2. How can we determine the equation of a circle given any two points on its circumference?
  3. What is the equation of a circle if its radius is doubled?
  4. How can this equation be derived if the center is shifted to (2,3)(2, 3)?
  5. How can you find the distance between a point and the center of the circle?

Tip: When working with equations of circles, always identify the center and radius first, as they directly define the equation.

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Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Circles

Formulas

(x - h)^2 + (y - k)^2 = r^2

Theorems

Standard equation of a circle

Suitable Grade Level

Grades 9-12