Math Problem Statement

Find the equation of the line shown on the graph.

Solution

The problem asks for the equation of the line shown on the graph.

From the image:

  1. Identifying two points: Let's pick two points that the line passes through. Looking at the graph:

    • Point 1: (5,2)(-5, 2)
    • Point 2: (3,2)(3, -2)
  2. Find the slope (mm): The slope of a line is calculated using the formula: m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1} Substituting the values of the two points: m=223(5)=48=12m = \frac{-2 - 2}{3 - (-5)} = \frac{-4}{8} = -\frac{1}{2} So, the slope m=12m = -\frac{1}{2}.

  3. Find the equation using the point-slope form: The equation of a line in point-slope form is: yy1=m(xx1)y - y_1 = m(x - x_1) Using one of the points, say (5,2)(-5, 2), and the slope m=12m = -\frac{1}{2}, the equation becomes: y2=12(x+5)y - 2 = -\frac{1}{2}(x + 5) Simplifying: y2=12x52y - 2 = -\frac{1}{2}x - \frac{5}{2} y=12x52+2y = -\frac{1}{2}x - \frac{5}{2} + 2 y=12x12y = -\frac{1}{2}x - \frac{1}{2}

Thus, the equation of the line is: y=12x12y = -\frac{1}{2}x - \frac{1}{2}

Would you like further details on any step, or do you have any questions?

Here are 5 related questions to practice:

  1. What would the equation be if the slope was positive?
  2. How do you calculate the y-intercept directly from the equation?
  3. Can you rewrite the equation in standard form?
  4. What is the slope-intercept form of a line, and how does it relate to this equation?
  5. How do you find the equation of a line if you only have its slope and y-intercept?

Tip: Always double-check the points chosen from a graph for accuracy when calculating the slope!

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Math Problem Analysis

Mathematical Concepts

Linear Equations
Graphing
Slope-Intercept Form

Formulas

Slope formula: m = (y2 - y1) / (x2 - x1)
Point-slope form: y - y1 = m(x - x1)
Slope-intercept form: y = mx + b

Theorems

Slope Theorem
Linear Equation Properties

Suitable Grade Level

Grades 8-10