Math Problem Statement

Given Δ𝑃𝑄𝑅 with 𝑃(4;3), 𝑄(3;βˆ’2) and R(-2;0). The equation of line 𝑃𝑄 is 𝑦=5π‘₯+17 and D is the π‘₯ intercept of line 𝑃𝑄. 𝑀(π‘₯;𝑦) is midpoint of PR.If 𝑅 is the centre of a circle with radius 𝑄𝑅, determine the equation of the circle in the form π‘₯2+π‘šπ‘₯+𝑦2+𝑛𝑦=π‘Ÿ2

Solution

To find the equation of the circle, we need to identify the center and the radius of the circle. Here's the breakdown of the given information and how we'll approach the solution:

  1. Center of the Circle:
    The center of the circle is point R(βˆ’2,0)R(-2, 0).

  2. Radius of the Circle:
    The radius of the circle is the distance between points Q(3,βˆ’2)Q(3, -2) and R(βˆ’2,0)R(-2, 0).

  3. Equation of the Circle:
    The general form of the equation of a circle with center (h,k)(h, k) and radius rr is:
    (xβˆ’h)2+(yβˆ’k)2=r2(x - h)^2 + (y - k)^2 = r^2 Substituting the center R(βˆ’2,0)R(-2, 0), the equation becomes:
    (x+2)2+(yβˆ’0)2=r2(x + 2)^2 + (y - 0)^2 = r^2

Step-by-Step Solution:

1. Find the Radius rr:

The radius rr is the distance between points Q(3,βˆ’2)Q(3, -2) and R(βˆ’2,0)R(-2, 0).
The distance formula between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is:
Distance=(x2βˆ’x1)2+(y2βˆ’y1)2\text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Substitute the coordinates of points QQ and RR:
r=(βˆ’2βˆ’3)2+(0βˆ’(βˆ’2))2r = \sqrt{(-2 - 3)^2 + (0 - (-2))^2}

2. Expand and Simplify to Find r2r^2:

Let's compute the value of r2r^2.The value of r2r^2 is 29. Thus, the radius rr of the circle is 29\sqrt{29}.

3. Write the Equation of the Circle:

Substitute the center R(βˆ’2,0)R(-2, 0) and r2=29r^2 = 29 into the standard equation of a circle: (x+2)2+y2=29(x + 2)^2 + y^2 = 29

4. Expand to the Desired Form:

Now, expand and rewrite the equation in the form x2+mx+y2+ny=r2x^2 + mx + y^2 + ny = r^2.

(x+2)2+y2=29β€…β€ŠβŸΉβ€…β€Šx2+4x+4+y2=29(x + 2)^2 + y^2 = 29 \implies x^2 + 4x + 4 + y^2 = 29

Simplify to:

x2+y2+4x=25x^2 + y^2 + 4x = 25

Here, the equation is in the form x2+mx+y2+ny=r2x^2 + mx + y^2 + ny = r^2 with:

  • m=4m = 4
  • n=0n = 0
  • r2=25r^2 = 25

Final Answer:

The equation of the circle is:

x2+4x+y2=25x^2 + 4x + y^2 = 25

Would you like more details or have any questions about the steps? Here are some related questions you might find interesting:

  1. How do you find the equation of a circle given two points on the circle?
  2. What is the significance of the midpoint formula in geometry?
  3. How do you determine if a point lies on a given circle?
  4. How do you derive the distance formula from the Pythagorean theorem?
  5. What are some real-life applications of circles in mathematics?

Tip: Always double-check your calculations when using the distance formula to ensure accuracy.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Circle Equations
Distance Formula

Formulas

Distance formula
Equation of a circle

Theorems

-

Suitable Grade Level

Grades 10-12