Math Problem Statement
For a reversible process, the following equation describes the entropy changes of the universe, system, and surroundings. ΔSuniv = ΔSsys + ΔSsurr = 0 For an irreversible process, the following equation applies. ΔSuniv = ΔSsys + ΔSsurr > 0 For each of the following processes, predict whether ΔSsurr is positive, negative, or zero. (a) Isothermally expanding a gas, ΔSsys > 0:
positive negative zero
(b) Reacting hydrogen and oxygen gas, ΔSsys < 0:
positive negative zero
Solution
For these questions, we need to predict the sign of (the entropy change of the surroundings) based on the entropy change of the system, , and whether the process is reversible or irreversible.
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Isothermal expansion of a gas ()
- When a gas expands isothermally, the entropy of the system increases because the molecules have more space to occupy, leading to increased disorder.
- Since , if this process is carried out in a reversible manner, would be negative (to ensure ).
- For an irreversible process, , so while might still be negative, it would be smaller in magnitude than to result in a positive .
Answer: is likely negative.
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Reaction between hydrogen and oxygen gas ()
- In this reaction, hydrogen and oxygen combine to form water, which is a more ordered (lower entropy) state than the gaseous reactants, so .
- For this exothermic reaction, heat is released to the surroundings, increasing the entropy of the surroundings.
- Thus, is positive because the surroundings gain entropy as they absorb the released heat.
Answer: is positive.
Let me know if you'd like further details or have questions.
Related Questions:
- How does temperature affect during an exothermic reaction?
- What would happen to if both and were negative?
- In a reversible process, can be non-zero while remains zero?
- How does the entropy change of a system compare between reversible and irreversible expansions?
- Can an endothermic reaction ever have a positive ?
Tip: For isothermal processes, remember that any heat transferred impacts both system and surroundings, influencing their entropy changes in opposite directions.
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Math Problem Analysis
Mathematical Concepts
Thermodynamics
Entropy
Irreversible and Reversible Processes
Formulas
ΔSuniv = ΔSsys + ΔSsurr
ΔSuniv = 0 for reversible processes
ΔSuniv > 0 for irreversible processes
Theorems
Second Law of Thermodynamics
Suitable Grade Level
Undergraduate level (Chemistry or Physics)
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