Math Problem Statement

Given the following equation of an ellipse, what is the length of the minor axis? \[ \frac{(y+1)^2}{25} + \frac{(x+2)^2}{4} = 1 \] Given the following equation of a hyperbola, mark all the statements that are true: \[ \frac{(y-2)^2}{4} - \frac{(x-5)^2}{1} = 1 \]

Solution

Let's solve the problems step-by-step:


Question 9:

The given equation of the ellipse is:

(y+1)225+(x+2)24=1\frac{(y+1)^2}{25} + \frac{(x+2)^2}{4} = 1

This is the standard form of an ellipse, where:

  • a2=25a^2 = 25 (larger denominator, semi-major axis squared),
  • b2=4b^2 = 4 (smaller denominator, semi-minor axis squared).

The length of the minor axis is 2b2b: b=4=2b = \sqrt{4} = 2 Length of the minor axis: 2b=2×2=4\text{Length of the minor axis: } 2b = 2 \times 2 = 4

Answer for Question 9: The length of the minor axis is 4.


Question 10:

The given equation of the hyperbola is:

(y2)24(x5)21=1\frac{(y-2)^2}{4} - \frac{(x-5)^2}{1} = 1

This is the standard form of a vertical hyperbola, where:

  • Center: (h,k)=(5,2)(h, k) = (5, 2),
  • a2=4a^2 = 4, so a=4=2a = \sqrt{4} = 2,
  • b2=1b^2 = 1, so b=1=1b = \sqrt{1} = 1,
  • The slopes of the asymptotes are ±ab=±21=±2\pm \frac{a}{b} = \pm \frac{2}{1} = \pm 2.

Analyzing the given statements:

  1. The vertices are (5, 0) and (5, 4):

    • For a vertical hyperbola, the vertices are at (h,k±a)=(5,2±2)=(5,0)(h, k \pm a) = (5, 2 \pm 2) = (5, 0) and (5,4)(5, 4).
    • This is true.
  2. The vertices are (4, 2) and (6, 2):

    • These would be correct for a horizontal hyperbola, but this hyperbola is vertical.
    • This is false.
  3. The foci are (5,5±2)(5, 5 \pm \sqrt{2}):

    • The foci are (h,k±c)(h, k \pm c), where c=a2+b2=4+1=5c = \sqrt{a^2 + b^2} = \sqrt{4 + 1} = \sqrt{5}.
    • The correct foci are (5,2±5)(5, 2 \pm \sqrt{5}), not (5,5±2)(5, 5 \pm \sqrt{2}).
    • This is false.
  4. The slope of the asymptotes is ±2\pm 2:

    • As calculated earlier, the slopes of the asymptotes are ±2\pm 2.
    • This is true.
  5. The slope of the asymptotes is ±12\pm \frac{1}{2}:

    • This is incorrect because the slope is ±2\pm 2.
    • This is false.
  6. The center is (5, 2):

    • From the equation, the center is (5,2)(5, 2).
    • This is true.

Correct answers for Question 10:

  • The vertices are (5, 0) and (5, 4).
  • The slope of the asymptotes is ±2\pm 2.
  • The center is (5, 2).

Would you like further clarification or additional details?

Related Questions:

  1. How do you determine whether a hyperbola is horizontal or vertical?
  2. What is the difference between the vertices and co-vertices of an ellipse?
  3. How is the length of the major axis of an ellipse calculated?
  4. Can a hyperbola ever have a slope of asymptotes as zero? Why or why not?
  5. What role does cc (focal distance) play in the definition of conic sections?

Tip:

To determine the orientation of a hyperbola, always check the sign and order of the squared terms in its standard equation.

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Math Problem Analysis

Mathematical Concepts

Ellipse
Hyperbola
Conic Sections
Geometry

Formulas

Ellipse equation: \( \frac{(y-k)^2}{a^2} + \frac{(x-h)^2}{b^2} = 1 \)
Hyperbola equation: \( \frac{(y-k)^2}{a^2} - \frac{(x-h)^2}{b^2} = 1 \)
Length of minor axis: \( 2b \)

Theorems

Conic Sections
Properties of Ellipses
Properties of Hyperbolas

Suitable Grade Level

Grades 10-12