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A uniform electric field with a magnitude of 1100 N/C points in the negative x direction, as shown in the figure. What is the difference in electric potential, ΔV=VB−VA , between points A and B?

In this problem, we are asked to find the difference in electric potential (\( \Delta V = V_B - V_A \)) between points A and B in the presence of a uniform electric field \( \vec{E} \) with a magnitude of 1100 N/C pointing in the negative x-direction.

### Key information:
- The electric field is uniform and points in the negative x-direction, meaning that the electric potential decreases in the direction of the field.
- The distance between points A and B along the x-axis is 4.0 cm = 0.04 m (as shown in the diagram).
- The electric field strength is \( E = 1100 \, \text{N/C} \).

### Formula for potential difference:

The electric potential difference between two points in a uniform electric field is given by:

\[
\Delta V = - E \cdot d
\]

Where:
- \( E \) is the magnitude of the electric field,
- \( d \) is the displacement in the direction of the electric field.

Since the electric field is along the x-direction and we are concerned with the x-displacement between points A and B, the displacement \( d \) is the horizontal distance between A and B, which is 4.0 cm = 0.04 m.

Now, let's calculate the potential difference \( \Delta V = V_B - V_A \):

\[
\Delta V = - E \cdot d = - (1100 \, \text{N/C}) \cdot (0.04 \, \text{m})
\]

Let me calculate the exact value.The electric potential difference between points A and B is:

\[
\Delta V = V_B - V_A = -44.0 \, \text{V}
\]

This means that point B is at a lower potential than point A by 44 volts.

Would you like further explanation or more details? Here are some additional related questions to consider:

1. What is the potential difference between points A and C?
2. How does the electric potential change if the electric field strength increases?
3. What is the relationship between electric field direction and potential difference?
4. How does the angle between the displacement vector and electric field affect the potential difference?
5. What would happen if the electric field were directed along the positive x-direction?

**Tip**: The potential difference in a uniform electric field depends only on the displacement along the direction of the field, not the total distance traveled.

A uniform electric field with a magnitude of 1100 N/C points in the negative x direction, as shown in the figure. What is the difference in electric potential, ΔV=VB−VA, between points A and B?

This problem involves calculating the electric potential difference between two points in a uniform electric field of 1100 N/C. Learn the key concepts and use the formula ΔV = - E ⋅ d to find the potential difference between points A and B, covering important physics concepts for Grades 11-12.

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