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The problem you've provided involves calculating the electric field for a charged solid sphere with a given charge and radius at various distances from its center. Here's the information extracted:

- The solid sphere has a charge of \( Q = 700 \, \mu C = 700 \times 10^{-6} \, C \).
- The radius of the sphere is \( R = 6 \, cm = 0.06 \, m \).
- You need to calculate the electric field \( E \) at different distances from the center:
  - (a) \( r = 3 \, cm = 0.03 \, m \) (inside the sphere),
  - (b) \( r = 6 \, cm = 0.06 \, m \) (on the surface),
  - (c) \( r = 20 \, cm = 0.20 \, m \) (outside the sphere).

### Approach:

#### 1. For **outside the sphere** \( (r > R) \):

The electric field outside a charged sphere behaves as if all the charge were concentrated at its center. This is given by:

\[
E = \frac{1}{4 \pi \epsilon_0} \frac{Q}{r^2}
\]

where:
- \( Q \) is the total charge,
- \( r \) is the distance from the center,
- \( \epsilon_0 = 8.854 \times 10^{-12} \, C^2/N \cdot m^2 \) is the vacuum permittivity.

#### 2. For **inside the sphere** \( (r < R) \):

The electric field inside a uniformly charged solid sphere is given by:

\[
E = \frac{1}{4 \pi \epsilon_0} \frac{Q}{R^3} \cdot r
\]

where:
- \( R \) is the radius of the sphere,
- \( r \) is the distance from the center,
- \( Q \) is the total charge.

Let's calculate the electric field for each case.The electric field at the specified distances from the center of the charged solid sphere is as follows:

- (a) At \( r = 3 \, cm \) (inside the sphere): \( E = 873.79 \, \text{MN/C} \)
- (b) At \( r = 6 \, cm \) (on the surface of the sphere): \( E = 1747.58 \, \text{MN/C} \)
- (c) At \( r = 20 \, cm \) (outside the sphere): \( E = 157.28 \, \text{MN/C} \)

Would you like further details or explanations about these results?

Here are 5 related questions:
1. How does the electric field behave inside a uniformly charged sphere?
2. What happens to the electric field at distances much larger than the sphere's radius?
3. How does changing the radius of the sphere affect the electric field inside?
4. What if the charge distribution was non-uniform? How would the electric field change?
5. How would the result differ if the sphere were hollow instead of solid?

**Tip:** The electric field inside a uniformly charged solid sphere increases linearly with distance from the center until it reaches the surface, where it behaves like a point charge.

Bola pejal bermuatan 700 μC memiliki jari-jari sebesar 6 cm. Hitunglah kuat medan listrik pada jarak: a. 3 cm dari pusat bola, b. 6 cm dari pusat bola, c. 20 cm dari pusat bola.

Calculate the electric field for a solid sphere with a charge of 700 μC and a radius of 6 cm at different distances (3 cm, 6 cm, 20 cm) from its center. Includes step-by-step explanations using electrostatics and Gauss's Law.

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