Math Problem Statement

Consider a semiconductor in thermal equilibrium (no current). Assume that the donor concentration varies as 

Nd(x)Nd(x)

=

N0N0

exp(-10x) over the range 0

≤≤

x

≤≤

0.1 m ,where 

N0N0

 is constant . assume T=300K what is the value of electric field?

(a) 2.6 V/m   (b) 2.6 N0 V/m   (c) 0.26 V/m   (d) 0.52 N0 V/m

Solution

To determine the electric field in a semiconductor with a spatially varying donor concentration Nd(x)N_d(x), we use the relationship derived from the drift-diffusion equation in thermal equilibrium. The electric field E(x)E(x) can be calculated using the following formula:

E(x)=kTqd(lnNd(x))dxE(x) = \frac{kT}{q} \frac{d(\ln N_d(x))}{dx}

Where:

  • kk is the Boltzmann constant (1.38×10231.38 \times 10^{-23} J/K),
  • TT is the temperature (given as 300 K),
  • qq is the charge of an electron (1.6×10191.6 \times 10^{-19} C),
  • Nd(x)N_d(x) is the donor concentration as a function of position.

Given Nd(x)=N0exp(10x)N_d(x) = N_0 \exp(-10x), we can proceed as follows:

  1. First, calculate the logarithm of Nd(x)N_d(x):

ln(Nd(x))=ln(N0exp(10x))=ln(N0)10x\ln(N_d(x)) = \ln(N_0 \exp(-10x)) = \ln(N_0) - 10x

  1. Take the derivative of ln(Nd(x))\ln(N_d(x)) with respect to xx:

d(lnNd(x))dx=10\frac{d(\ln N_d(x))}{dx} = -10

  1. Substitute the values into the electric field equation:

E(x)=kTq×(10)E(x) = \frac{kT}{q} \times (-10)

Given T=300T = 300 K, the constants are:

kTq=(1.38×1023 J/K)×(300 K)1.6×1019 C0.0259 V\frac{kT}{q} = \frac{(1.38 \times 10^{-23} \text{ J/K}) \times (300 \text{ K})}{1.6 \times 10^{-19} \text{ C}} \approx 0.0259 \text{ V}

Thus,

E(x)=0.0259×(10)=0.259 V/mE(x) = 0.0259 \times (-10) = -0.259 \text{ V/m}

The magnitude of the electric field is:

E(x)0.26 V/m|E(x)| \approx 0.26 \text{ V/m}

This corresponds to option (c) 0.26 V/m.


Do you want any more details or have any questions?

Here are some related questions:

  1. How does a varying donor concentration affect the electric field in a semiconductor?
  2. What is the significance of thermal equilibrium in semiconductors?
  3. How does the temperature influence the electric field in a semiconductor?
  4. What are the implications of a negative electric field value in this context?
  5. Can you explain the drift-diffusion model in more detail?
  6. How would the electric field change if the temperature were different?
  7. What would happen to the electric field if the donor concentration had a different spatial variation?
  8. How do you calculate the potential difference across the semiconductor from the electric field?

Tip: Always consider the temperature dependence when calculating electric fields in semiconductors, as it plays a crucial role in determining the electric field magnitude.

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Math Problem Analysis

Mathematical Concepts

Semiconductor Physics
Thermal Equilibrium
Electric Field Calculation

Formulas

Electric field in semiconductors: E(x) = (kT/q) * d(ln(N_d(x)))/dx

Theorems

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Suitable Grade Level

Advanced College