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To determine the elastic energy \( U \) stored in the compressed spring, we can use the formula for the potential energy stored in a spring:

\[
U = \frac{1}{2} k x^2
\]

where:
- \( k = 297 \, \text{N/m} \) is the spring constant,
- \( x = 0.7 \, \text{m} \) is the displacement of the spring from its equilibrium position.

### Step-by-Step Calculation
1. Substitute the values for \( k \) and \( x \) into the formula:

\[
U = \frac{1}{2} \times 297 \times (0.7)^2
\]

2. Calculate \( (0.7)^2 \):

\[
(0.7)^2 = 0.49
\]

3. Substitute this value back in:

\[
U = \frac{1}{2} \times 297 \times 0.49
\]

4. Perform the multiplication:

\[
297 \times 0.49 = 145.53
\]

5. Now, multiply by \( \frac{1}{2} \):

\[
U = \frac{1}{2} \times 145.53 = 72.765
\]

### Final Answer
The elastic energy stored in the spring is approximately:

\[
U \approx 72.77 \, \text{J}
\]

Let me know if you'd like further details or have any questions!

### Related Questions
1. How would the energy change if the spring were compressed by only 0.5 m?
2. What would happen to the energy stored if the spring constant \( k \) were doubled?
3. How much force is required to compress the spring by 0.7 m?
4. If friction were present, how would it affect the blocks' motion once the spring is released?
5. How would the system change if both blocks were connected by a string?

### Tip
Remember, the energy stored in a spring increases with the square of the displacement, so small changes in compression can significantly affect the energy stored!

Determine the elastic energy U stored in a compressed spring with a spring constant of 297 N/m and a compression distance of 0.7 m.

Learn how to calculate the elastic energy stored in a spring with a spring constant of 297 N/m when compressed by 0.7 m. This problem involves elastic potential energy and uses Hooke's Law, suitable for high school physics students in Grades 11-12.

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