The problem you've uploaded describes a one-dimensional elastic collision between two bodies, A and B, both having the same mass. The velocities before the collision are:

• Velocity of body A before the collision: $v_A = 3 \, \text{m/s}$
• Velocity of body B before the collision: $v_B = 4 \, \text{m/s}$

We need to determine the velocity of body B after the collision.

Key concept: Elastic Collision in One Dimension

In an elastic collision, both momentum and kinetic energy are conserved.

For two bodies of equal mass in a one-dimensional elastic collision, a special rule applies: the bodies exchange their velocities. This simplifies our calculation significantly.

Conclusion:

After the collision:

• The velocity of body A will become $v'_A = 4 \, \text{m/s}$ (initial velocity of B)
• The velocity of body B will become $v'_B = 3 \, \text{m/s}$ (initial velocity of A)

Thus, the velocity of body B after the collision is 3 m/s.

Would you like more details on the derivation or further explanation of elastic collisions?

Here are 5 related questions to expand on this topic:

1. How does the conservation of momentum apply in elastic collisions?
2. What happens if the masses of the two bodies are not equal?
3. How does this problem change if the collision is in two dimensions?
4. Can we calculate the kinetic energy before and after the collision to verify the energy conservation?
5. What is the difference between elastic and inelastic collisions?

Tip: In one-dimensional elastic collisions, when the masses of the two objects are the same, they always exchange velocities, making the calculations simpler!