Math Problem Statement

Let A be a 3x3 matrix. Suppose that A has eigenvalues 2 and 1, and suppose that u and v are eigenvectors corresponding to 2 and 1, respectively, where u = [1, 0, -1] and v = [2, 1, 0]. Then compute A^5 w, where w = [7, 2, -3].

Solution

The problem asks to compute A5wA^5 w, where AA is a 3×33 \times 3 matrix with eigenvalues 2 and 1. The eigenvectors corresponding to these eigenvalues are:

  • u=[101]u = \begin{bmatrix} 1 \\ 0 \\ -1 \end{bmatrix}, corresponding to the eigenvalue 22,
  • v=[210]v = \begin{bmatrix} 2 \\ 1 \\ 0 \end{bmatrix}, corresponding to the eigenvalue 11.

Additionally, we are given the vector w=[723]w = \begin{bmatrix} 7 \\ 2 \\ -3 \end{bmatrix}.

Approach:

  1. Eigenvalue Decomposition: Since uu and vv are eigenvectors of AA, we can express ww as a linear combination of the eigenvectors: w=c1u+c2vw = c_1 u + c_2 v We need to solve for c1c_1 and c2c_2.

  2. Apply the Matrix Power: Once we find c1c_1 and c2c_2, we use the property of powers of matrices with eigenvalues: Anu=λ1nuandAnv=λ2nvA^n u = \lambda_1^n u \quad \text{and} \quad A^n v = \lambda_2^n v So, A5w=c1A5u+c2A5v=c125u+c215vA^5 w = c_1 A^5 u + c_2 A^5 v = c_1 \cdot 2^5 u + c_2 \cdot 1^5 v

Let me first solve for the constants c1c_1 and c2c_2.It seems that the approach I used doesn't directly work because we only have two eigenvectors uu and vv, but we are dealing with a 3-dimensional vector space. Thus, the system matrix must be expanded to account for a third eigenvector or generalized eigenvector to complete the basis for the 3D space.

Since we are given two eigenvalues (2 and 1) and their corresponding eigenvectors, we need to explore a potential third eigenvector. If AA is a diagonalizable matrix, the third vector must be linearly independent from uu and vv, and it should correspond to either of the eigenvalues.

However, without explicit information on the third eigenvector, we can project ww onto the known eigenvectors to approximate the solution. I'll solve it using this decomposition approach. Let me proceed with that calculation.To handle this, we'll project ww onto the known eigenvectors uu and vv. Since these eigenvectors form part of the basis, we assume that ww can be expressed as a linear combination of the two eigenvectors, as follows:

w=c1u+c2vw = c_1 u + c_2 v

I'll now solve for the coefficients c1c_1 and c2c_2 using a least-squares approximation, which will allow us to approximate ww as a combination of these two vectors.It seems like I can’t do more advanced data analysis right now. Please try again later.

If you'd like, I can help guide you through the manual steps of solving for c1c_1 and c2c_2 using projections, or you could retry uploading or running the calculation. Let me know how you'd like to proceed!

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Eigenvalues
Eigenvectors
Matrix Powers

Formulas

A^n u = λ^n u
A^n v = λ^n v
w = c1 u + c2 v
A^5 w = c1 2^5 u + c2 1^5 v

Theorems

Eigenvalue decomposition
Matrix diagonalization

Suitable Grade Level

Undergraduate Linear Algebra