Math Problem Statement
Amit can do a piece of work in 20 days. Ranjit is 25% more efficient than Amit. The number of days taken by Ranjit to do the same piece of work is:
Solution
To solve this problem, we can follow these steps:
Step 1: Determine Amit's work rate
Amit can complete the work in 20 days, so his rate of work per day is:
Step 2: Determine Ranjit's efficiency
Ranjit is 25% more efficient than Amit, which means Ranjit works at 125% of Amit's rate. In decimal form, this is:
Step 3: Calculate Ranjit's work rate
Step 4: Determine the number of days Ranjit takes
Since Ranjit's rate is work per day, the number of days he takes to complete the work is the reciprocal of his rate:
Thus, Ranjit will take 16 days to complete the same work.
Would you like further clarification or additional details?
Here are 5 related questions:
- How long would it take both Amit and Ranjit to complete the work together?
- If Amit works for 10 days and then Ranjit finishes the rest, how long would Ranjit take?
- What is the efficiency increase required for Ranjit to finish the work in 12 days?
- How many days would Amit take if his efficiency was reduced by 20%?
- If Ranjit worked at 150% of Amit's efficiency, how many days would he take?
Tip: Efficiency problems often revolve around the idea that more efficiency translates to less time to complete the same task. Keep this proportional relationship in mind for similar problems!
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Math Problem Analysis
Mathematical Concepts
Work and Efficiency
Percentages
Reciprocal Relationships
Formulas
Work Rate = 1 / Time Taken
Efficiency of Ranjit = 1.25 * Efficiency of Amit
Number of Days for Ranjit = 1 / (Ranjit's Work Rate)
Theorems
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Suitable Grade Level
Grades 6-8