Math Problem Statement

The first pattern has 5 dots, the second pattern has 12 dots, and the 3rd pattern has 21 dots. How many dots does the 10th pattern have?

Solution

We can observe that the number of dots in each pattern seems to follow a certain pattern itself. Let's analyze the given sequence:

  • 1st pattern: 5 dots
  • 2nd pattern: 12 dots
  • 3rd pattern: 21 dots

To find how the number of dots changes, let's look at the differences between consecutive terms:

125=712 - 5 = 7 2112=921 - 12 = 9

It appears that the differences are increasing by 2. This suggests that the sequence might be quadratic in nature. We can assume the number of dots follows a quadratic formula of the form:

n=an2+bn+cn = an^2 + bn + c

Where nn is the pattern number, and aa, bb, and cc are constants we need to determine. Using the given data points, we can set up the following system of equations:

  1. For the first pattern (n=1n = 1, dots=5dots = 5):
    a(1)2+b(1)+c=5a+b+c=5a(1)^2 + b(1) + c = 5 \quad \Rightarrow \quad a + b + c = 5
  2. For the second pattern (n=2n = 2, dots=12dots = 12):
    a(2)2+b(2)+c=124a+2b+c=12a(2)^2 + b(2) + c = 12 \quad \Rightarrow \quad 4a + 2b + c = 12
  3. For the third pattern (n=3n = 3, dots=21dots = 21):
    a(3)2+b(3)+c=219a+3b+c=21a(3)^2 + b(3) + c = 21 \quad \Rightarrow \quad 9a + 3b + c = 21

Now, solving this system of equations:

  1. a+b+c=5a + b + c = 5
  2. 4a+2b+c=124a + 2b + c = 12
  3. 9a+3b+c=219a + 3b + c = 21

Subtracting the first equation from the second:

(4a+2b+c)(a+b+c)=125(4a + 2b + c) - (a + b + c) = 12 - 5 3a+b=7b=73a3a + b = 7 \quad \Rightarrow \quad b = 7 - 3a

Next, subtract the second equation from the third:

(9a+3b+c)(4a+2b+c)=2112(9a + 3b + c) - (4a + 2b + c) = 21 - 12 5a+b=9b=95a5a + b = 9 \quad \Rightarrow \quad b = 9 - 5a

Now, equating the two expressions for bb:

73a=95a7 - 3a = 9 - 5a 2a=2a=12a = 2 \quad \Rightarrow \quad a = 1

Substitute a=1a = 1 into b=73ab = 7 - 3a:

b=73(1)=4b = 7 - 3(1) = 4

Now substitute a=1a = 1 and b=4b = 4 into the first equation:

1+4+c=5c=01 + 4 + c = 5 \quad \Rightarrow \quad c = 0

Thus, the quadratic formula for the number of dots is:

n=n2+4nn = n^2 + 4n

To find the number of dots in the 10th pattern, substitute n=10n = 10 into the formula:

n=102+4(10)=100+40=140n = 10^2 + 4(10) = 100 + 40 = 140

So, the 10th pattern has 140 dots.

Would you like further details on the process, or do you have other questions?


Related Questions:

  1. How would the sequence change if the second pattern had 15 dots instead of 12?
  2. Can you generalize this method to find a formula for any quadratic sequence?
  3. How can we verify if a sequence is quadratic using differences?
  4. What is the significance of the constant term cc in the quadratic formula?
  5. How would the result change if the differences between consecutive dots increased by a different number?

Tip: When dealing with sequences where differences between terms increase steadily, always consider checking for a quadratic relationship by calculating second differences!

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Math Problem Analysis

Mathematical Concepts

Quadratic Sequences
Difference Analysis
Pattern Recognition

Formulas

Quadratic formula for sequences: n^2 + bn + c
General term for quadratic sequences

Theorems

Arithmetic progression for differences
Quadratic sequence second difference property

Suitable Grade Level

Grades 8-10