Math Problem Statement

The height of a projectile, h, is a function of the time, t it is in the air. The height in feet for t seconds is given by the function h(t). a. What is the domain of the function?

Solution

To determine the domain of the function h(t)h(t), which represents the height of a projectile as a function of time tt, we need to consider the physical context of the problem.

The domain of h(t)h(t) represents all the possible values of tt for which the height is defined and meaningful. Since tt represents time, it must be a non-negative value, as time cannot be negative in this context. Additionally, the time tt will only be valid from the moment the projectile is launched (at t=0t = 0) until the moment it hits the ground.

Thus, the domain of h(t)h(t) is:

Domain of h(t):t[0,T]\text{Domain of } h(t): \, t \in [0, T]

where TT is the time when the projectile hits the ground. The specific value of TT depends on the details of the function h(t)h(t) (like initial velocity, height, and gravity), but generally, TT is the time when h(t)=0h(t) = 0 after being launched.

Would you like to go into further details about determining TT or have any other questions?

Here are 5 related questions you might consider:

  1. How do you calculate the maximum height of the projectile?
  2. What is the general form of the function h(t)h(t) for a projectile?
  3. How does the initial velocity affect the time TT when the projectile hits the ground?
  4. What factors influence the shape of the h(t)h(t) graph?
  5. How do you find the time at which the projectile reaches its maximum height?

Tip: Understanding the domain in physical problems often involves considering the realistic constraints of the situation, such as non-negative time and conditions when the object is in motion.

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Math Problem Analysis

Mathematical Concepts

Projectile Motion
Quadratic Functions
Domain of a Function

Formulas

h(t) = -16t^2 + vt + s (for vertical projectile motion in feet)

Theorems

Theorem of Quadratic Roots (for solving when h(t) = 0)

Suitable Grade Level

Grades 9-11