To determine the domain of $f(x) = \log(2 - x)$, we need to ensure that the argument of the logarithmic function, $2 - x$, is strictly greater than 0. Logarithms are only defined for positive arguments.

Steps to Solve:

1. Set up the inequality: $2 - x > 0$

2. Solve for $x$: $-x > -2 \quad \text{(Divide by -1, flip the inequality)} \quad x < 2$

Thus, $x$ must be less than 2. The domain of $f(x)$ is: $(-\infty, 2)$

Final Answer:

The domain of $f(x) = \log(2 - x)$ in interval notation is: $(-\infty, 2)$

Would you like me to clarify further or provide more examples? Here are some related questions for practice:

1. What is the domain of $f(x) = \log(x^2 - 4)$?
2. How do you determine the domain of a square root function combined with logarithms?
3. What happens to the domain if $2 - x$ were inside $\log_b(2 - x^2)$?