To find the domain of the function $f(x) = \log(x - 16)$, we need to identify where the argument inside the logarithm is positive.

For the logarithmic function $\log(x - 16)$ to be defined, the expression inside the logarithm must be greater than 0:

$x - 16 > 0$

Solving this inequality:

$x > 16$

Thus, the domain of the function $f(x)$ is all $x$ values greater than 16. In interval notation, this is written as:

$(16, \infty)$

Would you like further details on this solution or have any additional questions?

Here are some related questions to explore:

1. What is the domain of $f(x) = \log(2x + 3)$?
2. How does the base of the logarithm affect the domain of a function?
3. What happens to the graph of $f(x) = \log(x - 16)$ as $x$ approaches 16 from the right?
4. Can the logarithm function ever be negative?
5. How do you find the domain of a composition of functions involving logarithms?

Tip: Always remember that the argument of a logarithmic function must be strictly positive.