Math Problem Statement
Solution
It looks like the page contains a series of division problems with two-digit divisors. I will help guide you through one of these examples, and you can apply the method to others.
Let's take the first division problem as an example:
Here’s how you can solve this:
Step 1: Estimate the first digit
- Check how many times 91 can go into 190. Since 91 is close to 100, we estimate that it goes into 190 approximately 2 times (since , which is close to 190).
Step 2: Perform the multiplication
- Multiply 91 by 2:
Step 3: Subtract the result from 190
- Now subtract:
Step 4: Bring down the next digit (if any)
- Since the problem does not have more digits to bring down, the remainder is 8.
Thus, the quotient for is 2 with a remainder of 8.
You can follow similar steps for the other problems. Would you like help with any specific one from the list?
Let me know if you want further details or clarifications. Here are five relative questions to extend this topic:
- What is the general rule for long division when dealing with remainders?
- How can you use estimation to simplify division problems with larger divisors?
- What strategies are helpful when dividing numbers that do not divide evenly?
- How can you convert a remainder into a decimal in division problems?
- What are the common mistakes to avoid when performing long division?
Tip: Always check your estimate in the first step by multiplying to ensure you're close to the correct quotient. This reduces errors later in the process!
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Math Problem Analysis
Mathematical Concepts
Long Division
Division with Remainders
Formulas
Quotient = Dividend ÷ Divisor
Remainder = Dividend - (Divisor × Quotient)
Theorems
Division Algorithm: For any integers a and b (b > 0), there exist unique integers q and r such that a = bq + r, where 0 ≤ r < b.
Suitable Grade Level
Grades 4-6