Math Problem Statement

Which one of the following number is divisible by 5 and 6 both?

Solution

To find which number is divisible by both 5 and 6, we need to determine the least common multiple (LCM) of 5 and 6. The LCM of two numbers is the smallest number that is divisible by both.

  1. The prime factorization of 5 is: 515^1
  2. The prime factorization of 6 is: 21×312^1 \times 3^1

To get the LCM, we take the highest powers of all prime factors involved:

LCM(5,6)=21×31×51=30\text{LCM}(5, 6) = 2^1 \times 3^1 \times 5^1 = 30

Thus, any number divisible by both 5 and 6 must be divisible by 30. If you're given a list of numbers, you should check which one is divisible by 30.

If you provide a list, I can help identify the correct number.

Would you like more details or have any further questions? Here are five related questions for exploration:

  1. How do you calculate the LCM for other numbers?
  2. Can a number be divisible by 5 but not 6?
  3. How can you quickly identify if a number is divisible by 5 or 6?
  4. What is the difference between GCD and LCM?
  5. What are some other common divisibility rules?

Tip: A number divisible by 5 will always end in 0 or 5!

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Math Problem Analysis

Mathematical Concepts

Number Theory
Divisibility
Least Common Multiple (LCM)

Formulas

LCM(a, b) = (a * b) / GCD(a, b)
LCM(5, 6) = 30

Theorems

Least Common Multiple (LCM)
Prime Factorization

Suitable Grade Level

Grades 6-8