Math Problem Statement

a line segment AB has a length of 20 units.point C divides the line segment AB in the ratio 2:3

Solution

Given that point CC divides the line segment ABAB in the ratio 2:3, the total ratio is 5 parts (2 + 3). The segment ABAB has a total length of 20 units.

To find the length of segments ACAC and CBCB:

  1. Length of ACAC (which corresponds to the 2 parts): AC=25×20=8 unitsAC = \frac{2}{5} \times 20 = 8 \text{ units}

  2. Length of CBCB (which corresponds to the 3 parts): CB=35×20=12 unitsCB = \frac{3}{5} \times 20 = 12 \text{ units}

Thus, point CC divides ABAB into:

  • AC=8AC = 8 units
  • CB=12CB = 12 units

Would you like further details or have any questions?

Here are 5 related questions:

  1. How do you find the coordinates of CC given AA and BB's coordinates?
  2. What is the midpoint formula for a line segment?
  3. How do you generalize division of a line segment in a given ratio?
  4. How can we apply this concept to a 3D line segment?
  5. What is the difference between external and internal division of a line segment?

Tip: When dividing a line segment in a given ratio, always ensure the sum of the parts matches the total length of the segment.

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Math Problem Analysis

Mathematical Concepts

Geometry
Ratio and Proportion
Line Segments

Formulas

Division of a line segment in a given ratio: AC = (m / (m+n)) * AB and CB = (n / (m+n)) * AB

Theorems

Section Formula (used to divide a line segment into a given ratio)

Suitable Grade Level

Grades 8-10