https://file.aiquickdraw.com/mathbot/file/1729628134962l3jyx4je.jpg

The division problem shown in the image is:

\[
2,840 \div 23
\]

### Step-by-step solution:
1. **Divide the first digits**: 
   - 23 goes into 28 **1** time.
   - \( 1 \times 23 = 23 \), so subtract: \( 28 - 23 = 5 \).
   
2. **Bring down the next digit**: 
   - Bring down the **4** from 2,840, making the new number **54**.
   - 23 goes into 54 **2** times.
   - \( 2 \times 23 = 46 \), so subtract: \( 54 - 46 = 8 \).

3. **Bring down the last digit**: 
   - Bring down the **0**, making the new number **80**.
   - 23 goes into 80 **3** times.
   - \( 3 \times 23 = 69 \), so subtract: \( 80 - 69 = 11 \).

4. **Remainder**: 
   - Since the remainder is 11 (and less than 23), the division does not divide evenly.

### Final Answer:
- The quotient is **123**, with a remainder of **11**.
- Thus, **Option A** is correct:
  - **Quotient = 123, Remainder = 11**.

Would you like further clarification or a breakdown of a specific part?

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Here are 5 related questions you might find helpful:
1. What is the relationship between division, multiplication, and remainders?
2. How do you verify the answer of a long division problem?
3. Can all numbers be divided without leaving a remainder?
4. What is the difference between quotient and remainder?
5. How does long division differ from modular arithmetic?

**Tip:** You can always check your division by multiplying the quotient by the divisor and adding the remainder!

Divide 2,840 by 23, and fill in the quotient and remainder.

Learn how to divide 2,840 by 23 using long division. This problem demonstrates the division algorithm, quotient, and remainder concepts, suitable for students in Grades 4-6.

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