Consider the point P = (3, 2). In following cases, find the distance from P to the line l.l passes through A(0, 5) and B(8, −1).

To find the distance from the point \( P = (3, 2) \) to the line passing through points \( A(0, 5) \) and \( B(8, -1) \), we can use the formula for the distance from a point to a line:

\[
d = \frac{|Ax_1 + By_1 + C|}{\sqrt{A^2 + B^2}}
\]

Where:
- \( A \), \( B \), and \( C \) are the coefficients of the line equation in standard form \( Ax + By + C = 0 \).
- \( (x_1, y_1) \) are the coordinates of the point \( P \).

### Step 1: Find the equation of the line through \( A(0, 5) \) and \( B(8, -1) \).
First, calculate the slope \( m \) of the line through \( A(0, 5) \) and \( B(8, -1) \):

\[
m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-1 - 5}{8 - 0} = \frac{-6}{8} = -\frac{3}{4}
\]

Now, using the point-slope form of a line equation:

\[
y - y_1 = m(x - x_1)
\]

Substitute \( m = -\frac{3}{4} \) and \( (x_1, y_1) = (0, 5) \):

\[
y - 5 = -\frac{3}{4}(x - 0)
\]

\[
y - 5 = -\frac{3}{4}x
\]

Multiply through by 4 to eliminate the fraction:

\[
4(y - 5) = -3x
\]

\[
4y - 20 = -3x
\]

Rearrange into the standard form:

\[
3x + 4y - 20 = 0
\]

So, the equation of the line is \( 3x + 4y - 20 = 0 \).

### Step 2: Use the distance formula.
Now, apply the distance formula with \( A = 3 \), \( B = 4 \), and \( C = -20 \), and \( (x_1, y_1) = (3, 2) \):

\[
d = \frac{|3(3) + 4(2) - 20|}{\sqrt{3^2 + 4^2}}
\]

\[
d = \frac{|9 + 8 - 20|}{\sqrt{9 + 16}}
\]

\[
d = \frac{|9 + 8 - 20|}{5} = \frac{|17 - 20|}{5} = \frac{|-3|}{5} = \frac{3}{5}
\]

### Final Answer:
The distance from point \( P = (3, 2) \) to the line passing through \( A(0, 5) \) and \( B(8, -1) \) is \( \frac{3}{5} \) units.

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Would you like more details on any part of the solution, or do you have any questions?

Here are some follow-up questions related to the topic:
1. How would you find the distance between two points instead of from a point to a line?
2. How can the point-slope form of a line help in different cases of line equations?
3. What changes in the distance formula if the line equation has different coefficients?
4. How do you derive the general formula for the distance between a point and a line?
5. Can the formula be applied in 3D geometry?

**Tip**: To find the equation of a line given two points, always start by finding the slope and then use the point-slope form.

Consider the point P = (3, 2). In following cases, find the distance from P to the line l. l passes through A(0, 5) and B(8, −1).

Learn how to find the distance from point P(3, 2) to a line passing through points A(0, 5) and B(8, -1) using the distance formula. This detailed solution covers concepts from analytic geometry, including calculating the slope and line equation. Suitable for students in Grades 9-12.

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