https://file.aiquickdraw.com/mathbot/file/17254148119320npkbuxd.jpg

To solve the problem in the image, let's analyze it step by step.

### Problem Breakdown:
1. **Initial Data:**
   - The car travels 120 miles in 2 hours.
   - Speed of the car = \( \frac{120 \text{ miles}}{2 \text{ hours}} = 60 \text{ mph} \).

2. **Scenario Change:**
   - The car now travels at half the original speed, so the new speed is \( \frac{60 \text{ mph}}{2} = 30 \text{ mph} \).
   - The car travels for five times as long as before. The original time was 2 hours, so the new time is \( 2 \text{ hours} \times 5 = 10 \text{ hours} \).

3. **Distance Calculation:**
   - Distance \( D \) is given by the formula: \( D = \text{Speed} \times \text{Time} \).
   - Substituting the new values: \( D = 30 \text{ mph} \times 10 \text{ hours} = 300 \text{ miles} \).

### Answer:
The car travels **300 miles**.

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Would you like more details or have any further questions?

### Related Questions:
1. What would be the distance if the car traveled three times as long at the original speed?
2. If the car traveled for 4 hours at the new speed, how far would it go?
3. How long would it take the car to travel 200 miles at the new speed?
4. If the car's speed doubled instead of halving, how far would it travel in 2 hours?
5. How does changing the speed affect the time needed to cover a fixed distance?

### Tip:
Always check the units when calculating speed, distance, and time to ensure consistency and accuracy.

A car travels 120 miles in 2 hours at a speed of 60 mph. If the car travels half as fast but five times as long, how far does it travel?

Solve the problem of calculating the distance a car travels when its speed is halved and travel time is quintupled. This problem illustrates key concepts in distance, speed, and time, making it suitable for middle school students.

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