Math Problem Statement

Find the distance, d, between points A(2, 1) and B(-4, 7).

Solution

We are asked to find the distance between points A(2,1)A(2, 1) and B(4,7)B(-4, 7). The formula for the distance between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) in the coordinate plane is given by:

d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Step 1: Substitute the coordinates into the formula.

  • x1=2x_1 = 2, y1=1y_1 = 1
  • x2=4x_2 = -4, y2=7y_2 = 7

d=((4)2)2+(71)2d = \sqrt{((-4) - 2)^2 + (7 - 1)^2} d=(6)2+(6)2d = \sqrt{(-6)^2 + (6)^2} d=36+36d = \sqrt{36 + 36} d=72d = \sqrt{72} d8.5(rounded to the nearest tenth)d \approx 8.5 \quad \text{(rounded to the nearest tenth)}

Thus, the distance dd is approximately 8.5.

Would you like a detailed explanation or have any questions?

Here are 5 related questions to further explore this concept:

  1. How would you find the midpoint of segment ABAB?
  2. How can you use the distance formula in three-dimensional space?
  3. What is the equation of a circle with center A(2,1)A(2, 1) and radius equal to the distance dd?
  4. How does the Pythagorean theorem relate to the distance formula?
  5. How do you find the slope of the line passing through points AA and BB?

Tip: The distance formula is essentially the Pythagorean theorem applied in the coordinate plane!

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Math Problem Analysis

Mathematical Concepts

Geometry
Coordinate Geometry
Distance Between Two Points

Formulas

Distance formula: d = √((x₂ - x₁)² + (y₂ - y₁)²)

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 8-10