Math Problem Statement

A bird flies 10 km from point A to point B on a bearing of N80oE. Another bird flies 9 km from point A to C on a bearing of S70oW. Find BC, the distance between the birds.

Solution

To find the distance BCBC between the birds at points BB and CC, we can first determine the coordinates of points BB and CC using their respective bearings and distances from point AA.

Step 1: Determine Coordinates of B and C

  1. Point B:

    • Distance: 1010 km
    • Bearing: N80EN80^\circ E (which means 8080^\circ clockwise from North)
    • Coordinates:
      • xB=10sin(80)x_B = 10 \sin(80^\circ)
      • yB=10cos(80)y_B = 10 \cos(80^\circ)
  2. Point C:

    • Distance: 99 km
    • Bearing: S70WS70^\circ W (which means 7070^\circ clockwise from South, or 180+70=250180^\circ + 70^\circ = 250^\circ from North)
    • Coordinates:
      • xC=9sin(250)x_C = 9 \sin(250^\circ)
      • yC=9cos(250)y_C = 9 \cos(250^\circ)

Step 2: Calculate Coordinates

Now let's calculate the coordinates for points BB and CC:

  • For point BB:

    • xB=10sin(80)10×0.98489.848x_B = 10 \sin(80^\circ) \approx 10 \times 0.9848 \approx 9.848 km
    • yB=10cos(80)10×0.17361.736y_B = 10 \cos(80^\circ) \approx 10 \times 0.1736 \approx 1.736 km
    • Thus, B(9.848,1.736)B \approx (9.848, 1.736).
  • For point CC:

    • xC=9sin(250)9×(0.9397)8.457x_C = 9 \sin(250^\circ) \approx 9 \times (-0.9397) \approx -8.457 km
    • yC=9cos(250)9×(0.3420)3.078y_C = 9 \cos(250^\circ) \approx 9 \times (-0.3420) \approx -3.078 km
    • Thus, C(8.457,3.078)C \approx (-8.457, -3.078).

Step 3: Find Distance BC

Using the distance formula: BC=(xBxC)2+(yByC)2BC = \sqrt{(x_B - x_C)^2 + (y_B - y_C)^2}

Substituting the coordinates: BC=(9.848(8.457))2+(1.736(3.078))2BC = \sqrt{(9.848 - (-8.457))^2 + (1.736 - (-3.078))^2} =(9.848+8.457)2+(1.736+3.078)2= \sqrt{(9.848 + 8.457)^2 + (1.736 + 3.078)^2} =(18.305)2+(4.814)2= \sqrt{(18.305)^2 + (4.814)^2} =334.522+23.167= \sqrt{334.522 + 23.167} =357.68918.9 km= \sqrt{357.689} \approx 18.9 \text{ km}

Conclusion

The distance BCBC between the two birds is approximately 18.918.9 km.

Would you like more details on any part of the calculation? Here are some related questions:

  1. How would the distance change if the bearings were altered?
  2. What are the implications of the bearing directions on the birds' paths?
  3. How do you convert bearings to standard coordinate angles?
  4. What other methods can be used to find distances between points on a plane?
  5. Can you explain how to visualize this problem using a diagram?

Tip: Always ensure your angles are in the correct mode (degrees vs. radians) when using a calculator!

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Coordinate Geometry
Distance Calculation

Formulas

Distance formula: BC = sqrt((x_B - x_C)^2 + (y_B - y_C)^2)
Trigonometric functions for coordinates

Theorems

Law of Cosines (indirectly applied through distance formula)

Suitable Grade Level

Grades 10-12