Math Problem Statement

A wheel with a radius of 0.40 m rolls without slipping along a horizontal floor, as shown in the figure. P is a dot painted on the rim of the wheel. At time t1, P is at the point of contact between the wheel and the floor. At a later time, t2, the wheel has rolled through one-half of a revolution. What is the displacement of P during this time interval?

A wheel with a radius of 0.40 m rolls without slipping along a horizontal floor, as shown in the figure. P is a dot painted on the rim of the wheel. At time t1, P is at the point of contact between the wheel and the floor. At a later time, t2, the wheel has rolled through one-half of a revolution. What is the displacement of P during this time interval?

Solution

The problem involves a wheel rolling without slipping, and you need to find the displacement of point PP, which is marked on the rim of the wheel. Let's break this down step by step:

Given:

  • Radius of the wheel, r=0.40mr = 0.40 \, \text{m}.
  • The wheel rolls without slipping.
  • Point PP is initially at the point of contact between the wheel and the floor at time t1t_1.
  • By time t2t_2, the wheel has rolled through half a revolution.

Understanding the motion:

When the wheel rolls without slipping, the point on the rim (point PP) traces a cycloidal path. At t1t_1, PP is in contact with the ground, and by t2t_2, after half a revolution, PP is at the highest point on the wheel.

In one-half revolution:

  • The wheel moves horizontally by a distance equal to half the circumference of the wheel.

    • Circumference of the wheel = 2πr=2π(0.40)=2.513m2\pi r = 2\pi(0.40) = 2.513 \, \text{m}.
    • Half the circumference = πr=π(0.40)=1.257m\pi r = \pi(0.40) = 1.257 \, \text{m}.
  • Vertically, point PP moves from the ground to the top of the wheel, a vertical distance equal to the wheel's diameter (since point PP is now at the top of the wheel after half a revolution).

    • Vertical displacement = 2r=2(0.40)=0.80m2r = 2(0.40) = 0.80 \, \text{m}.

Total displacement of point PP:

The displacement of PP is the straight-line distance between its initial and final positions. This is a combination of horizontal and vertical displacements, which form a right triangle. The hypotenuse (total displacement) can be found using the Pythagorean theorem:

d=(horizontal displacement)2+(vertical displacement)2d = \sqrt{(\text{horizontal displacement})^2 + (\text{vertical displacement})^2}

d=(1.257)2+(0.80)2d = \sqrt{(1.257)^2 + (0.80)^2}

d=1.580+0.640=2.221.49md = \sqrt{1.580 + 0.640} = \sqrt{2.22} \approx 1.49 \, \text{m}

Final Answer:

The displacement of point PP after the wheel has rolled through half a revolution is approximately 1.49 meters.

Would you like further details or clarifications? Here are some related questions to deepen understanding:

  1. How would the displacement change if the radius of the wheel were doubled?
  2. What is the velocity of point PP when it is at the highest point of the wheel?
  3. How would the displacement change if the wheel rolled through a full revolution?
  4. Can you describe the cycloidal path traced by point PP in this scenario?
  5. How does rolling without slipping differ from sliding motion in this context?

Tip: For rolling without slipping, the velocity of the point of contact with the ground is momentarily zero at the instant it touches the surface.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Circular Motion
Displacement
Pythagorean Theorem

Formulas

Circumference of a circle = 2πr
Pythagorean Theorem: d = √(horizontal_displacement^2 + vertical_displacement^2)

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 9-12