Let's solve the given questions in the image.

Question 1:

A man starts walking towards the south. After walking for 10 m, he turns left at a right angle. Then after walking for 15 m, he again turns left at a right angle. In what direction is he finally walking?

• Solution:

  • Initially, the man is walking South.
  • After walking 10 m, he turns left, so now he is walking East.
  • Then, after walking 15 m, he again turns left, so now he is walking North.

• Answer: North (option (a)).

Question 2:

If the girl is facing North, then: (a) In which direction and how far is the point C from point B?
(b) In which direction is the point D?
(c) Through what angle should the girl turn to face the point F?

Part (a):

• From the diagram, point C is 40 m to the North-East of point B.

• Using Pythagoras’ theorem, the distance between B and C can be calculated:

  • $BC = 40 \, \text{m}$ (as it is explicitly mentioned in the question).

• Answer: Point C is 40 m to the North-East of point B.

Part (b):

• From the diagram, point D is directly to the South-East of the girl.
• Answer: Point D is in the South-East direction.

Part (c):

• To face point F, the girl needs to turn from facing North to South-East.

• The angle of turn required is $180^\circ - 60^\circ = 120^\circ$ (clockwise).

• Answer: The girl should turn 120° clockwise to face point F.

Would you like detailed step-by-step calculations for any of the above solutions? Let me know!

Related Questions:

1. If the man turned right instead of left in Question 1, which direction would he end up walking?
2. What is the shortest distance from point B to point D based on the diagram?
3. How would the direction to point F change if the girl initially faced South?
4. What angle should the girl turn if she initially faced East to face point C?
5. Calculate the distance between points C and D using their directions.

Tip:

When solving directional problems, always sketch the directions step by step to avoid confusion and ensure accuracy.