Math Problem Statement

Write a function describing the relationship of the given variables. p varies directly with the square of q and when q = 7, p = 441.

Solution

The question asks to write a function describing the relationship between variables pp and qq, where it states that pp varies directly with the square of qq.

Step-by-step solution:

  1. General form of direct variation with the square: Since pp varies directly with the square of qq, the general relationship is: p=kq2p = kq^2 where kk is the constant of proportionality.

  2. Use the given values to find kk: The problem gives us that when q=7q = 7, p=441p = 441. Substituting these values into the equation: 441=k(72)441 = k(7^2) 441=k(49)441 = k(49) Solving for kk: k=44149=9k = \frac{441}{49} = 9

  3. Write the final equation: Now that we know k=9k = 9, the function relating pp and qq is: p=9q2p = 9q^2

  4. Check with the provided input q=63q = 63: The question shows an input where q=63q = 63. To find pp, substitute q=63q = 63 into the equation: p=9(632)p = 9(63^2) First, calculate 63263^2: 632=396963^2 = 3969 Then: p=9×3969=35721p = 9 \times 3969 = 35721 So, p=35721p = 35721 when q=63q = 63.

If you'd like more details or have any further questions, feel free to ask!

Here are 5 related questions:

  1. What does "direct variation" mean in mathematical terms?
  2. How do you calculate the square of a number, and what are some shortcuts?
  3. If pp varied inversely with the square of qq, how would the formula change?
  4. What are some real-life examples of variables that vary directly with the square of another variable?
  5. How would you solve this problem if the variation was with the cube of qq?

Tip: When solving problems involving direct variation, always look for the constant of proportionality by using the values provided.

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Math Problem Analysis

Mathematical Concepts

Direct Variation
Proportionality
Quadratic Relationships

Formulas

p = kq^2

Theorems

Direct Variation Theorem

Suitable Grade Level

Grades 8-10