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The problem states that \( y \) is directly proportional to the square root of \( (x + 2) \). This relationship can be written as:

\[
y = k \sqrt{x + 2}
\]

where \( k \) is the constant of proportionality. We are also given that when \( x = 7 \), \( y = 2 \). We can use this information to find \( k \), and then use that value to find \( y \) when \( x = 98 \).

### Step 1: Find the constant \( k \)

When \( x = 7 \) and \( y = 2 \), substitute these values into the equation:

\[
2 = k \sqrt{7 + 2}
\]
\[
2 = k \sqrt{9}
\]
\[
2 = k \times 3
\]
\[
k = \frac{2}{3}
\]

### Step 2: Find \( y \

y is directly proportional to the square root of (x + 2). When x = 7, y = 2. Find y when x = 98.

Solve a direct proportionality problem where y is directly proportional to the square root of (x + 2). Given that when x = 7, y = 2, find y when x = 98. This problem includes solving for the constant of proportionality and applying the square root formula. Suitable for students in Grades 8-10.

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