Math Problem Statement

Let v_i = (v_i^(1), v_i^(2), v_i^(3), v_i^(4)), for i = 1, 2, 3, 4, be four vectors in R^4 such that ∑_{i=1}^4 v_i^(j) = 0, for each j = 1, 2, 3, 4. Let W be the subspace of R^4 spanned by {v_1, v_2, v_3, v_4}. Then the dimension of W over R cannot be: (a) 1, (b) 2, (c) 3, (d) None of these.

Solution

Problem Analysis

We are given four vectors v1,v2,v3,v4R4v_1, v_2, v_3, v_4 \in \mathbb{R}^4 such that:

vi=(vi(1)vi(2)vi(3)vi(4))for i=1,2,3,4,v_i = \begin{pmatrix} v_i^{(1)} \\ v_i^{(2)} \\ v_i^{(3)} \\ v_i^{(4)} \end{pmatrix} \quad \text{for } i = 1, 2, 3, 4, and the condition:

i=14vi(j)=0for each j=1,2,3,4.\sum_{i=1}^4 v_i^{(j)} = 0 \quad \text{for each } j = 1, 2, 3, 4.

We are tasked with determining the possible dimensions of the subspace WW of R4\mathbb{R}^4 spanned by {v1,v2,v3,v4}\{v_1, v_2, v_3, v_4\}, and identifying which dimension WW cannot have.


Step 1: Understanding the condition

The condition:

i=14vi(j)=0for each j=1,2,3,4\sum_{i=1}^4 v_i^{(j)} = 0 \quad \text{for each } j = 1, 2, 3, 4

means that the sum of the ii-th components of all the vectors is zero. This implies a linear dependence among the vectors. Specifically, the four vectors v1,v2,v3,v4v_1, v_2, v_3, v_4 cannot all be linearly independent in R4\mathbb{R}^4.


Step 2: Maximum possible dimension of WW

  • {v1,v2,v3,v4}\{v_1, v_2, v_3, v_4\} is a set of at most 4 vectors in R4\mathbb{R}^4, so the dimension of WW can be at most 4.
  • However, the condition i=14vi(j)=0\sum_{i=1}^4 v_i^{(j)} = 0 imposes constraints, reducing the linear independence of the vectors.

Step 3: Minimum possible dimension of WW

Since the vectors are not trivial (not all zero), the minimum possible dimension of WW is 1.


Step 4: Using the dependency condition

The condition i=14vi(j)=0\sum_{i=1}^4 v_i^{(j)} = 0 creates a dependency among the vectors. Specifically, this condition can be rewritten as:

v4=(v1+v2+v3).v_4 = -(v_1 + v_2 + v_3).

Thus, v4v_4 is determined by v1,v2,v_1, v_2, and v3v_3. Therefore, {v1,v2,v3}\{v_1, v_2, v_3\} can span all of WW, making the dimension of WW at most 3.


Step 5: Conclusion

The dimension of WW cannot be 4 due to the dependency among the vectors. Therefore, the answer is:

(c) 3\boxed{\text{(c) 3}}


Follow-up Questions

  1. Why does the condition i=14vi(j)=0\sum_{i=1}^4 v_i^{(j)} = 0 imply linear dependence among the vectors?
  2. Can the dimension of WW be 1, and under what conditions?
  3. How would the solution change if the vectors were in R5\mathbb{R}^5 instead of R4\mathbb{R}^4?
  4. What is the general relationship between the number of vectors and their span in Rn\mathbb{R}^n?
  5. Can you construct explicit examples of such vectors satisfying the given condition?

Tip

To determine the dimension of a subspace spanned by a set of vectors, always check for linear dependencies and apply the rank-nullity theorem or dependency relationships.

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Vector Spaces
Linear Dependence

Formulas

Sum of components condition ∑_{i=1}^4 v_i^(j) = 0

Theorems

Dimension theorem for vector spaces

Suitable Grade Level

Undergraduate Level