n order to create 2 L of 1.5m sucrose solution, what volume, of 6M sucrose needs to be diluted in water?

To solve this problem, we can use the dilution formula:

\[
C_1 V_1 = C_2 V_2
\]

Where:
- \( C_1 \) is the initial concentration (6M sucrose),
- \( V_1 \) is the initial volume of the more concentrated solution (the unknown we need to find),
- \( C_2 \) is the final concentration (1.5M sucrose),
- \( V_2 \) is the final volume (2 L).

We can rearrange this formula to solve for \( V_1 \):

\[
V_1 = \frac{C_2 V_2}{C_1}
\]

Substitute the given values:

\[
V_1 = \frac{1.5 \times 2}{6} = \frac{3}{6} = 0.5 \text{ L}
\]

So, 0.5 L (or 500 mL) of the 6M sucrose solution is needed to create 2 L of 1.5M sucrose solution.

Would you like more details on dilution or any related topic?

Here are 5 related questions:
1. What is the meaning of molarity (M) in solutions?
2. How do you calculate the number of moles of solute in a given solution?
3. What is the process for preparing a solution from a concentrated stock?
4. How do different concentrations affect the properties of a solution?
5. What role does dilution play in chemical reactions and lab preparations?

**Tip:** When diluting a solution, always add the solute to the solvent slowly, stirring continuously to ensure even mixing.

In order to create 2 L of 1.5M sucrose solution, what volume of 6M sucrose needs to be diluted in water?

Learn how to calculate the volume of 6M sucrose needed to create 2 L of 1.5M sucrose solution. This detailed solution uses the dilution formula C₁V₁ = C₂V₂, and explains key concepts such as molarity and dilution. Ideal for high school students in Grades 9-12.

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