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The question asks to find \( y_n \) if \( y = x^2 e^x \cos x \).

To find \( y_n \), we likely need to differentiate the given function multiple times, depending on the context of \( y_n \). Since \( y_n \) is often used to denote the \( n \)-th derivative of \( y \), I will proceed to find the first few derivatives and explain the process.

### Given:
\[ y = x^2 e^x \cos x \]

We'll need to use the product rule and chain rule since this expression involves products of functions of \( x \).

### First derivative \( y' \):
\[
y' = \frac{d}{dx}(x^2 e^x \cos x)
\]
Using the product rule \( (fg)' = f'g + fg' \), we treat \( x^2 \), \( e^x \), and \( \cos x \) as separate factors. Start by differentiating \( x^2 e^x \) first.

1. Differentiate \( x^2 \):
   \[
   \frac{d}{dx}(x^2) = 2x
   \]
2. Differentiate \( e^x \):
   \[
   \frac{d}{dx}(e^x) = e^x
   \]
3. Differentiate \( \cos x \):
   \[
   \frac{d}{dx}(\cos x) = -\sin x
   \]

Now, apply the product rule:
\[
y' = \frac{d}{dx}(x^2 e^x) \cdot \cos x + x^2 e^x \cdot \frac{d}{dx}(\cos x)
\]
\[
y' = (2x e^x + x^2 e^x) \cos x - x^2 e^x \sin x
\]

Thus, the first derivative is:
\[
y' = (2x e^x + x^2 e^x) \cos x - x^2 e^x \sin x
\]

Would you like me to proceed further with higher-order derivatives or clarify any part of this process? Here are some related questions that could deepen your understanding:

1. How is the product rule applied in differentiation?
2. What is the significance of the chain rule in the context of differentiation?
3. Could you use this method to differentiate other combinations of products like trigonometric and exponential functions?
4. What happens when you differentiate \( e^x \cos x \) multiple times?
5. How can the behavior of higher derivatives influence the shape of the graph of the function?

**Tip:** When dealing with multiple factors in differentiation, it's often easier to start by focusing on two factors at a time and gradually expanding the product rule to handle all terms.

Learn how to differentiate the function y = x^2 e^x cos x using the product rule and chain rule. This solution provides a detailed step-by-step guide to finding the first derivative, and higher-order derivatives if needed, suitable for calculus students.

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