Math Problem Statement

Differentiation of q square by d(q)

Solution

To differentiate q2q^2 with respect to qq, we apply the power rule for differentiation. The power rule states:

ddq(qn)=nqn1\frac{d}{dq} \left( q^n \right) = n q^{n-1}

In your case, q2q^2 has n=2n = 2. Applying the power rule:

ddq(q2)=2q21=2q\frac{d}{dq} \left( q^2 \right) = 2q^{2-1} = 2q

Thus, the derivative of q2q^2 with respect to qq is:

ddq(q2)=2q\frac{d}{dq} \left( q^2 \right) = 2q

Would you like more details or have any questions?

Here are 5 related questions to expand your understanding:

  1. What is the derivative of q3q^3 with respect to qq?
  2. How do you differentiate a constant times qnq^n, such as 5q25q^2?
  3. What is the derivative of q2+3qq^2 + 3q with respect to qq?
  4. How does the power rule apply to negative exponents, like q2q^{-2}?
  5. What is the second derivative of q2q^2 with respect to qq?

Tip: The power rule is one of the most fundamental rules in differentiation—it's crucial for simplifying many common functions!

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Math Problem Analysis

Mathematical Concepts

Calculus
Differentiation
Power Rule

Formulas

d/dq(q^n) = n*q^(n-1)

Theorems

Power Rule for Differentiation

Suitable Grade Level

Grades 10-12