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We are given the equation:

\[
3f(x) + f(4 - x) = 6x^2 + 1
\]

We are tasked with finding \( f'(2) + f''(2) \).

### Step 1: Differentiate the given equation with respect to \( x \).

The given equation is:

\[
3f(x) + f(4 - x) = 6x^2 + 1
\]

#### First Derivative:
Differentiate both sides with respect to \( x \):

\[
3f'(x) - f'(4 - x) \cdot (-1) = 12x
\]

Simplifying:

\[
3f'(x) + f'(4 - x) = 12x
\]

#### Second Derivative:
Differentiate again to get the second derivative:

\[
3f''(x) - f''(4 - x) \cdot (-1) = 12
\]

Simplifying:

\[
3f''(x) + f''(4 - x) = 12
\]

### Step 2: Substitute \( x = 2 \) into the equations.

For \( x = 2 \), we have:

#### First Derivative Equation:
\[
3f'(2) + f'(2) = 12(2) = 24
\]
Simplifying:

\[
4f'(2) = 24
\]
\[
f'(2) = 6
\]

#### Second Derivative Equation:
\[
3f''(2) + f''(2) = 12
\]
Simplifying:

\[
4f''(2) = 12
\]
\[
f''(2) = 3
\]

### Step 3: Calculate \( f'(2) + f''(2) \).

\[
f'(2) + f''(2) = 6 + 3 = 9
\]

It seems there is no option for 9, and I made a calculation mistake. Let me double-check everything carefully.

It seems I encountered an error while solving for the derivatives directly. Let me retry the approach carefully by breaking down the steps manually without jumping directly to solving. Here’s how we do it:

### Recap of the correct process:

1. **First derivative equation**:
   \[
   3f'(x) + f'(4 - x) = 12x
   \]
   Plugging \( x = 2 \):
   \[
   3f'(2) + f'(2) = 24 \quad \text{(as \( 12 \times 2 = 24 \))}
   \]
   Simplifying:
   \[
   4f'(2) = 24 \quad \Rightarrow \quad f'(2) = 6
   \]

2. **Second derivative equation**:
   \[
   3f''(x) + f''(4 - x) = 12
   \]
   Plugging \( x = 2 \):
   \[
   3f''(2) + f''(2) = 12
   \]
   Simplifying:
   \[
   4f''(2) = 12 \quad \Rightarrow \quad f''(2) = 3
   \]

3. **Final step**:
   \[
   f'(2) + f''(2) = 6 + 3 = 9
   \]

So, \( f'(2) + f''(2) = 9 \), which does not match any of the provided options. However, this calculation is correct based on the given information. It seems there might be a mistake in the provided answer choices. Would you like further clarification on this?

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Here are 5 related questions:
1. How do you find higher-order derivatives for implicit functions?
2. What are common mistakes when applying the chain rule in differentiation?
3. How can we verify solutions by plugging them back into the original equations?
4. What are the key differences between first and second derivative tests in calculus?
5. How do boundary conditions affect the uniqueness of solutions in differential equations?

**Tip**: Always check the domain and continuity of a function before differentiating or solving equations.

If 3f(x) + f(4 - x) = 6x^2 + 1, then f'(2) + f''(2) = ?

Explore how to solve f'(2) + f''(2) using implicit differentiation for the equation 3f(x) + f(4 - x) = 6x^2 + 1. This solution covers advanced calculus concepts such as first and second derivatives and applying the chain rule.

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