Math Problem Statement
Differentiate.
yΒ = sec(π) tan(π)
y'Β =Β Β
Solution
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Math Problem Analysis
Mathematical Concepts
Calculus
Trigonometry
Differentiation
Formulas
Product Rule: y' = f'(π)g(π) + f(π)g'(π)
Derivative of sec(π): d/dπ(sec(π)) = sec(π)tan(π)
Derivative of tan(π): d/dπ(tan(π)) = sec^2(π)
Theorems
Product Rule
Trigonometric Derivatives
Suitable Grade Level
Grades 11-12
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