Math Problem Statement

Продифференцируй функцию

Продифференцируй функцию

Solution

Let's differentiate the function step by step. The given function is:

y=ln(sin(arctan(e2x)))y = \ln \left( \sin \left( \sqrt{\arctan \left( e^{2x} \right)} \right) \right)

Step-by-step differentiation:

  1. Outer function: The outermost function is the natural logarithm ln(u)\ln(u), where u=sin(arctan(e2x))u = \sin \left( \sqrt{\arctan \left( e^{2x} \right)} \right).

    • The derivative of ln(u)\ln(u) with respect to uu is 1u\frac{1}{u}.
  2. First inner function: The next function is sin(v)\sin(v), where v=arctan(e2x)v = \sqrt{\arctan \left( e^{2x} \right)}.

    • The derivative of sin(v)\sin(v) with respect to vv is cos(v)\cos(v).
  3. Second inner function: The next function is the square root w\sqrt{w}, where w=arctan(e2x)w = \arctan \left( e^{2x} \right).

    • The derivative of w\sqrt{w} with respect to ww is 12w\frac{1}{2\sqrt{w}}.
  4. Third inner function: The next function is arctan(z)\arctan(z), where z=e2xz = e^{2x}.

    • The derivative of arctan(z)\arctan(z) with respect to zz is 11+z2\frac{1}{1+z^2}.
  5. Innermost function: The innermost function is e2xe^{2x}.

    • The derivative of e2xe^{2x} with respect to xx is 2e2x2e^{2x}.

Putting it all together:

By applying the chain rule, we differentiate each function with respect to its argument and multiply them together:

dydx=1sin(arctan(e2x))cos(arctan(e2x))12arctan(e2x)11+(e2x)22e2x\frac{dy}{dx} = \frac{1}{\sin \left( \sqrt{\arctan \left( e^{2x} \right)} \right)} \cdot \cos \left( \sqrt{\arctan \left( e^{2x} \right)} \right) \cdot \frac{1}{2 \sqrt{\arctan \left( e^{2x} \right)}} \cdot \frac{1}{1 + \left( e^{2x} \right)^2} \cdot 2e^{2x}

This is the derivative of the given function.

Would you like further details or clarification on any part of the differentiation? Here's a list of related questions to explore:

  1. How do you apply the chain rule to functions involving nested functions?
  2. What is the derivative of inverse trigonometric functions like arctan?
  3. How can you simplify complex derivatives step by step?
  4. Can you differentiate logarithmic functions involving trigonometric expressions?
  5. What are the common mistakes when differentiating nested functions?

Tip: When differentiating complex expressions, always carefully identify each nested function and apply the chain rule step by step.

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Math Problem Analysis

Mathematical Concepts

Differentiation
Nested Functions
Trigonometry
Logarithms
Exponential Functions

Formulas

Derivative of ln(u): d(ln(u))/dx = 1/u * du/dx
Derivative of sin(v): d(sin(v))/dx = cos(v) * dv/dx
Derivative of sqrt(w): d(sqrt(w))/dx = 1/(2 * sqrt(w)) * dw/dx
Derivative of arctan(z): d(arctan(z))/dx = 1/(1 + z^2) * dz/dx
Derivative of e^(2x): d(e^(2x))/dx = 2e^(2x)

Theorems

Chain Rule

Suitable Grade Level

Grades 11-12, University Calculus