Math Problem Statement

A2) Stellen Sie die Differentialgleichung auf, die den Zusammenhang zwischen der Spannung uAB und Strom i1 durch den Widerstand R1 in der folgenden Schaltung beschreibt. (Hinweis: Ermitteln Sie aus der Maschengleichung mit uAB i2 (Strom durch R2) und setze das Ergebnis in die Maschengleichung mit uL ein, nachdem iL (=Strom durch L) durch Verwendung der Knotengleichung durch i1 und i2 eliminiert wurde).

A2) Stellen Sie die Differentialgleichung auf, die den Zusammenhang zwischen der Spannung uAB und Strom i1 durch den Widerstand R1 in der folgenden Schaltung beschreibt. (Hinweis: Ermitteln Sie aus der Maschengleichung mit uAB i2 (Strom durch R2) und setze das Ergebnis in die Maschengleichung mit uL ein, nachdem iL (=Strom durch L) durch Verwendung der Knotengleichung durch i1 und i2 eliminiert wurde).

Solution

The circuit you've provided includes several components: resistors R1R_1 and R2R_2, an inductor LL, and a capacitor CC. The goal is to derive the differential equation that relates the voltage uABu_{AB} across points AA and BB with the current i1i_1 through resistor R1R_1. Let's break down the steps.

Step-by-Step Approach:

  1. Define the circuit currents:

    • Let i1i_1 be the current through R1R_1.
    • Let i2i_2 be the current through R2R_2.
    • The current through the inductor LL is iLi_L.
  2. KCL (Kirchhoff's Current Law) at the node where R1R_1, R2R_2, and LL meet: i1=i2+iLi_1 = i_2 + i_L So, the current through the inductor can be expressed as: iL=i1i2i_L = i_1 - i_2

  3. Voltage across resistor R2R_2 and inductor LL: Using Ohm’s law, the voltage across R2R_2 is: uR2=R2i2u_{R_2} = R_2 \cdot i_2 The voltage across the inductor LL is given by the inductance law: uL=LdiLdt=Ld(i1i2)dtu_L = L \frac{di_L}{dt} = L \frac{d(i_1 - i_2)}{dt}

  4. Mesh equations:

    • The total voltage uABu_{AB} can be expressed as: uAB=uR2+uLu_{AB} = u_{R_2} + u_L Substituting for uR2u_{R_2} and uLu_L: uAB=R2i2+Ld(i1i2)dtu_{AB} = R_2 i_2 + L \frac{d(i_1 - i_2)}{dt}
  5. Eliminate i2i_2: Using the mesh equation for the circuit involving R1R_1 and CC: uAB=R1i1+1Ci1dtu_{AB} = R_1 i_1 + \frac{1}{C} \int i_1 dt

  6. Combine everything: Now, we can substitute the expression for i2i_2 from the earlier steps, and differentiate appropriately to eliminate the integrals and express the relationship between uABu_{AB} and i1i_1.

This method will lead us to the final differential equation.

Would you like to explore the complete mathematical solution, or do you need clarification on any specific part of the process so far?

Here are some questions to further explore the concepts involved:

  1. How do you find the voltage-current relationship for inductors and capacitors?
  2. What is the role of Kirchhoff’s voltage and current laws in circuit analysis?
  3. How would the differential equation change if an additional resistor was added in parallel with the inductor?
  4. How does the energy stored in inductors and capacitors influence the transient response of the circuit?
  5. Can you derive a similar equation for the output voltage across the capacitor CC?

Tip: In RL and RC circuits, inductors resist changes in current and capacitors resist changes in voltage. These properties lead to differential equations governing their behavior.

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Math Problem Analysis

Mathematical Concepts

Circuit Analysis
Differential Equations
Kirchhoff's Laws

Formulas

Ohm's law: U = R * I
Inductor voltage: u_L = L * di/dt
Capacitor voltage: u_C = (1/C) * ∫ i dt
Kirchhoff's Current Law (KCL): i1 = i2 + iL

Theorems

Kirchhoff's Voltage Law (KVL)
Kirchhoff's Current Law (KCL)

Suitable Grade Level

Undergraduate (Electrical Engineering)