Math Problem Statement
Solution
Let's analyze the image, which appears to show a question related to the function .
(a) Sketch the graph of the function:
The correct graph for is a "V" shape, where:
- For , (a straight line with slope 1).
- For , (a straight line with slope -1).
In the image, the correct graph is the fourth one on the far right (which resembles a "V").
(b) For what values of is differentiable?
The function is differentiable everywhere except at , where there's a sharp corner. Hence, the function is differentiable for .
The correct option should be:
- , not all real as indicated in the image.
(c) Find a formula for :
The derivative of can be expressed as a piecewise function:
1 & \text{if } x > 0, \\ -1 & \text{if } x < 0, \\ \text{undefined} & \text{at } x = 0. \end{cases}$$ Let me know if you'd like further details or clarifications! Here are some related questions for practice: 1. How would the graph of $$g(x) = -|x|$$ differ from $$f(x) = |x|$$? 2. Why is $$f(x) = |x|$$ not differentiable at $$x = 0$$? 3. Can you describe the behavior of the second derivative $$f''(x)$$ for $$f(x) = |x|$$? 4. How would you evaluate $$f'(x)$$ using the limit definition of the derivative for $$f(x) = |x|$$? 5. What is the integral of $$f(x) = |x|$$ over the interval $$[-2, 2]$$? **Tip**: When determining differentiability, check for corners or cusps in the graph!Ask a new question for Free
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Math Problem Analysis
Mathematical Concepts
Absolute Value Functions
Differentiation
Piecewise Functions
Formulas
f'(x) = 1 if x > 0, f'(x) = -1 if x < 0
Theorems
Differentiability at points of non-smoothness (sharp corners)
Suitable Grade Level
Grades 11-12
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