Math Problem Statement

The sum of two numbers is 60 and their difference is 43 .The difference of there squares is?

Solution

We are given:

  • The sum of two numbers: x+y=60x + y = 60
  • The difference of two numbers: xy=43x - y = 43

We need to find the difference of their squares: x2y2x^2 - y^2.

Using the algebraic identity: x2y2=(x+y)(xy)x^2 - y^2 = (x + y)(x - y)

Substitute the known values into the formula: x2y2=(60)(43)x^2 - y^2 = (60)(43)

Now calculate: x2y2=2580x^2 - y^2 = 2580

So, the difference of their squares is 25802580.

Would you like more details or have any other questions?

Here are 5 related questions to consider:

  1. What happens when both numbers are equal?
  2. How can we find the individual values of xx and yy?
  3. What is the sum of their squares instead of the difference?
  4. How does the difference of squares formula apply in geometry?
  5. Can you generalize this approach for any two numbers?

Tip: The difference of squares formula is useful for quickly simplifying problems where two terms are subtracted after being squared.

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Math Problem Analysis

Mathematical Concepts

Algebra
Difference of Squares
Linear Equations

Formulas

x^2 - y^2 = (x + y)(x - y)

Theorems

Difference of Squares Theorem

Suitable Grade Level

Grades 7-9