Math Problem Statement

Suppose that f(x) is a continuous function on the closed interval [-1, 3] and that f(-1)=2, f(0)=6, f(1)=-5, f(2)=1, f(3)=-6. Which of the following statements is always TRUE for a function with these properties?

Solution

We are given that f(x)f(x) is a continuous function on the interval [1,3][-1, 3], with the following values:

f(1)=2,f(0)=6,f(1)=5,f(2)=1,f(3)=6f(-1) = 2, \quad f(0) = 6, \quad f(1) = -5, \quad f(2) = 1, \quad f(3) = -6

We need to determine which of the statements is always true given these properties. Let's analyze each one:

Statement A:

"The equation f(x)=0f(x) = 0 has no solutions for xx in the interval (1,0)(-1, 0)."

  • f(1)=2f(-1) = 2 and f(0)=6f(0) = 6, so f(x)f(x) is positive on the entire interval [1,0][-1, 0] and does not cross zero.
  • This means there are no solutions to f(x)=0f(x) = 0 in the interval (1,0)(-1, 0), so this statement is true.

Statement B:

"The equation f(x)=0f(x) = 0 has exactly one solution for xx in the interval (1,2)(1, 2)."

  • f(1)=5f(1) = -5 and f(2)=1f(2) = 1, so by the Intermediate Value Theorem (since f(x)f(x) is continuous), f(x)f(x) must cross zero exactly once between 1 and 2.
  • This statement is true.

Statement C:

"The equation f(x)=0f(x) = 0 has at least one solution for xx in the interval (1,0)(-1, 0)."

  • We already know from analyzing Statement A that there are no solutions for f(x)=0f(x) = 0 in (1,0)(-1, 0), so this statement is false.

Statement D:

"The equation f(x)=0f(x) = 0 has at least two solutions for xx in the interval (1,3)(1, 3)."

  • f(1)=5f(1) = -5, f(2)=1f(2) = 1, and f(3)=6f(3) = -6. By the Intermediate Value Theorem, f(x)f(x) must cross zero once between 1 and 2, and again between 2 and 3.
  • Thus, there are two solutions in (1,3)(1, 3), so this statement is true.

Statement E:

"The equation f(x)=0f(x) = 0 has exactly two solutions for xx in the interval (1,3)(1, 3)."

  • From the reasoning in Statement D, we know that f(x)=0f(x) = 0 crosses exactly once between 1 and 2, and again between 2 and 3, so there are exactly two solutions in this interval.
  • This statement is true.

Conclusion:

The statements A, B, D, and E are true, but the question asks for which statement is always true. Based on the options presented in the multiple-choice format, the correct answer is:

E. f(x)=0f(x) = 0 has exactly two solutions in the interval (1,3)(1, 3).


Would you like a more detailed explanation of the Intermediate Value Theorem, or do you have any other questions about the problem? Here are some related questions you might find helpful:

  1. What is the Intermediate Value Theorem, and how is it used in this problem?
  2. How do you determine the number of solutions to an equation involving a continuous function?
  3. Could there ever be more than two solutions for f(x)=0f(x) = 0 in the interval (1,3)(1, 3)?
  4. How does continuity affect the behavior of functions and their roots?
  5. How would the analysis change if f(x)f(x) were not continuous?

Tip: The Intermediate Value Theorem is a powerful tool when dealing with continuous functions and can help in determining when a function must cross a certain value, such as zero.

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Math Problem Analysis

Mathematical Concepts

Continuous Functions
Zeros of Functions
Intermediate Value Theorem

Formulas

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Theorems

Intermediate Value Theorem

Suitable Grade Level

Grades 11-12