The graph shows a parabola, and you are asked to find its x-intercepts. X-intercepts are the points where the parabola crosses the x-axis, which happens when $y = 0$.

From the graph:

• One x-intercept is at $x = -6$.
• The other x-intercept is at $x = -2$.

Thus, the coordinates of the x-intercepts are: $(-6, 0) \quad \text{and} \quad (-2, 0)$

Would you like more details, or do you have any questions?

Here are five related questions to think about:

1. How would you find the x-intercepts algebraically if the equation of the parabola was given?
2. What is the significance of the vertex of a parabola in relation to its x-intercepts?
3. Can a parabola have no x-intercepts? If so, under what conditions?
4. How do the values of the coefficients in the quadratic equation affect the x-intercepts?
5. How can you verify the x-intercepts using the quadratic formula?

Tip: The x-intercepts of a quadratic function are the solutions to the equation $ax^2 + bx + c = 0$, which can be solved using factoring, completing the square, or the quadratic formula.