Math Problem Statement

solve this

Solution

To determine the x-coordinate of the vertex of the quadratic function f(x)=ax2+bx+cf(x) = ax^2 + bx + c, where a0a \neq 0, we use the formula for the vertex of a parabola given by the quadratic function. The x-coordinate of the vertex is given by:

x=b2ax = -\frac{b}{2a}

So, the complete sentence would be:

The x-coordinate of the vertex of f(x)=ax2+bx+cf(x) = ax^2 + bx + c, a0a \neq 0, is b2a-\frac{b}{2a}.

Would you like more details or have any questions?

Here are 5 numbered questions for you to ask:

  1. What is the formula for finding the y-coordinate of the vertex of a quadratic function?
  2. How do you determine if a quadratic function opens upwards or downwards?
  3. Can you explain how to complete the square for a quadratic equation?
  4. What are the steps to derive the quadratic formula?
  5. How can you find the roots of a quadratic equation using factoring?

Tip: Always check the sign of the coefficient aa in a quadratic function to determine the direction in which the parabola opens. If a>0a > 0, it opens upwards; if a<0a < 0, it opens downwards.

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Math Problem Analysis

Mathematical Concepts

Quadratic Functions
Vertex of a Parabola

Formulas

Vertex formula: x = -b/(2a)

Theorems

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Suitable Grade Level

High School