Math Problem Statement

The received information is written in Hamming code 0101100. Determine the syndrome. Use odd parity.

Solution

To determine the syndrome for the Hamming code 01011000101100 with odd parity, we’ll follow these steps:

  1. Identify the Structure of the Code: A typical Hamming code in this format has a structure where specific bits are parity bits, and the remaining bits carry the data. Since it's not explicitly stated, I'll assume we're working with a (7,4)(7,4) Hamming code, where:

    • Parity bits are located at positions 1, 2, and 4.
    • Data bits are at positions 3, 5, 6, and 7.
  2. Label Each Bit Position: Code: 0  1  0  1  1  0  0\text{Code: } 0 \; 1 \; 0 \; 1 \; 1 \; 0 \; 0

    • Bit 1: Parity
    • Bit 2: Parity
    • Bit 3: Data
    • Bit 4: Parity
    • Bit 5: Data
    • Bit 6: Data
    • Bit 7: Data
  3. Check Parity Conditions: Since we are using odd parity, each parity bit should make the total number of 1's in its respective checked positions odd. Let's analyze each parity bit.

    • P1P_1 (Position 1) checks bits 1, 3, 5, and 7 (positions with a binary 1 in the first bit): 0,0,1,00, 0, 1, 0

      • Sum of bits: 0+0+1+0=10 + 0 + 1 + 0 = 1 (odd)
      • P1P_1 is correct.
    • P2P_2 (Position 2) checks bits 2, 3, 6, and 7 (positions with a binary 1 in the second bit): 1,0,0,01, 0, 0, 0

      • Sum of bits: 1+0+0+0=11 + 0 + 0 + 0 = 1 (odd)
      • P2P_2 is correct.
    • P4P_4 (Position 4) checks bits 4, 5, 6, and 7 (positions with a binary 1 in the third bit): 1,1,0,01, 1, 0, 0

      • Sum of bits: 1+1+0+0=21 + 1 + 0 + 0 = 2 (even)
      • P4P_4 is incorrect.
  4. Calculate the Syndrome: The syndrome is determined by the status of the parity bits. We’ll represent each parity check result as a binary digit: 0 for correct, 1 for incorrect.

    Syndrome: P4P2P1=100\text{Syndrome: } P_4 P_2 P_1 = 1 0 0

  5. Interpret the Syndrome: The syndrome 100100 in binary points to position 4, indicating that bit 4 is in error.

Conclusion:

The syndrome for the code 01011000101100 with odd parity is 100100, and it indicates an error in position 4.

Would you like further clarification on any part of this process?


Here are some related questions:

  1. How does even parity differ from odd parity in error detection?
  2. Can Hamming code correct multiple errors simultaneously?
  3. What are the applications of Hamming code in data transmission?
  4. How can the syndrome be interpreted for larger Hamming codes like (15,11)(15,11)?
  5. What would be the steps if we used even parity instead?

Tip: Always verify each parity bit separately to systematically locate the error in Hamming codes.

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Math Problem Analysis

Mathematical Concepts

Error Detection
Hamming Code
Parity Check

Formulas

Syndrome Calculation for Hamming Code
Parity Check using Odd Parity

Theorems

Hamming Code Error Detection and Correction

Suitable Grade Level

Grades 10-12