Math Problem Statement
jawab dengan akurat dan benar
Solution
To determine the value of so that the series
converges, we can simplify the expression and apply the convergence criteria for a series.
Solution Steps:
-
Simplify the Term: The given term is:
This simplifies the series to:
-
Analyze the Simplified Series: The series now looks like a -series, which takes the form:
A -series converges if . In our case, we have , which is greater than 1. Therefore, the series converges for any because the power of in the denominator is sufficient to ensure convergence.
Conclusion:
The series converges for any value of since the simplification led to a convergent -series with .
Would you like a deeper explanation of each step or have any questions?
Here are some related questions that expand on this topic:
- What are -series, and how is their convergence determined?
- Can you explain the Ratio Test and how it applies to series convergence?
- How does the comparison test work for determining series convergence?
- What happens if in the denominator changes to another function of ?
- How would convergence criteria change if we had an additional constant term in the numerator?
Tip: Understanding series convergence criteria like the -series test, Ratio Test, and Comparison Test can greatly help in quickly determining convergence for various types of series.
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Series Convergence
p-Series Test
Formulas
\( \sum_{n=1}^{\infty} \frac{1}{n^q} \) converges if \( q > 1 \)
Theorems
p-Series Convergence Theorem
Suitable Grade Level
Undergraduate Calculus
Related Recommendation
Determine Absolute Convergence of Series with \( \left( \frac{-n}{2n + 1} \right)^{5n} \)
Determining Convergence or Divergence of a Series Using the Ratio Test
Determining the Divergence of the Series \( \sum 1/(n^{2p} + n) \)
Determine Convergence of Series \( \sum \frac{15}{n^{1.5}} \) Using p-Series Test
Convergence of the Series \sum_{n=1}^\infty \frac{(n+2)!}{(n+5)^n}