Math Problem Statement

jawab dengan akurat dan benar

Tentukan nilai p sehingga deret \( \sum_{n=1}^{\infty} \frac{n^p}{n^{p+5}} \) konvergen.

Solution

To determine the value of pp so that the series

n=1npnp+5\sum_{n=1}^{\infty} \frac{n^p}{n^{p+5}}

converges, we can simplify the expression and apply the convergence criteria for a series.

Solution Steps:

  1. Simplify the Term: The given term is: npnp+5=np(p+5)=n5\frac{n^p}{n^{p+5}} = n^{p - (p+5)} = n^{-5}

    This simplifies the series to: n=11n5\sum_{n=1}^{\infty} \frac{1}{n^5}

  2. Analyze the Simplified Series: The series now looks like a pp-series, which takes the form: n=11nq\sum_{n=1}^{\infty} \frac{1}{n^q}

    A pp-series converges if q>1q > 1. In our case, we have q=5q = 5, which is greater than 1. Therefore, the series converges for any pp because the power of nn in the denominator is sufficient to ensure convergence.

Conclusion:

The series converges for any value of pp since the simplification led to a convergent pp-series with q=5q = 5.

Would you like a deeper explanation of each step or have any questions?


Here are some related questions that expand on this topic:

  1. What are pp-series, and how is their convergence determined?
  2. Can you explain the Ratio Test and how it applies to series convergence?
  3. How does the comparison test work for determining series convergence?
  4. What happens if p+5p+5 in the denominator changes to another function of nn?
  5. How would convergence criteria change if we had an additional constant term in the numerator?

Tip: Understanding series convergence criteria like the pp-series test, Ratio Test, and Comparison Test can greatly help in quickly determining convergence for various types of series.

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Math Problem Analysis

Mathematical Concepts

Series Convergence
p-Series Test

Formulas

\( \sum_{n=1}^{\infty} \frac{1}{n^q} \) converges if \( q > 1 \)

Theorems

p-Series Convergence Theorem

Suitable Grade Level

Undergraduate Calculus