Math Problem Statement

find whether if it is a square, whether the distance is the same, whether if it a 90 degree, and whther if it is parallel with it's opposite line

Solution

To determine if the given points (1,5)(-1,5), (3,2)(3,2), (4,1)(4,1), and (0,2)(0,-2) form a square, we need to check the following:

  1. Distance Between Adjacent Points: All four sides of a square should have equal length.
  2. 90-Degree Angles: The angles between the adjacent sides should be 90 degrees.
  3. Parallel Opposite Lines: Opposite sides should be parallel.

Let's go through each step systematically.

Step 1: Calculate the Distances Between Adjacent Points

The distance dd between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by:

d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Distances:

  1. Between (1,5)(-1,5) and (3,2)(3,2):

d1=(3(1))2+(25)2=(3+1)2+(3)2=42+(3)2=16+9=25=5d_1 = \sqrt{(3 - (-1))^2 + (2 - 5)^2} = \sqrt{(3 + 1)^2 + (-3)^2} = \sqrt{4^2 + (-3)^2} = \sqrt{16 + 9} = \sqrt{25} = 5

  1. Between (3,2)(3,2) and (4,1)(4,1):

d2=(43)2+(12)2=12+(1)2=1+1=21.414d_2 = \sqrt{(4 - 3)^2 + (1 - 2)^2} = \sqrt{1^2 + (-1)^2} = \sqrt{1 + 1} = \sqrt{2} \approx 1.414

  1. Between (4,1)(4,1) and (0,2)(0,-2):

d3=(04)2+(21)2=(4)2+(3)2=16+9=25=5d_3 = \sqrt{(0 - 4)^2 + (-2 - 1)^2} = \sqrt{(-4)^2 + (-3)^2} = \sqrt{16 + 9} = \sqrt{25} = 5

  1. Between (0,2)(0,-2) and (1,5)(-1,5):

d4=(10)2+(5(2))2=(1)2+72=1+49=507.071d_4 = \sqrt{(-1 - 0)^2 + (5 - (-2))^2} = \sqrt{(-1)^2 + 7^2} = \sqrt{1 + 49} = \sqrt{50} \approx 7.071

Step 2: Check if Adjacent Sides are Equal

  • d1=5d_1 = 5
  • d21.414d_2 \approx 1.414
  • d3=5d_3 = 5
  • d47.071d_4 \approx 7.071

Since all sides are not equal, the figure cannot be a square.

Step 3: Check if Angles Between Adjacent Sides are 90 Degrees

To verify if the angles are 90 degrees, we can calculate the slopes of the sides and check if the product of the slopes of two adjacent sides is 1-1 (which indicates perpendicularity).

The slope mm between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by:

m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}

Slopes:

  1. Between (1,5)(-1,5) and (3,2)(3,2):

m1=253(1)=34m_1 = \frac{2 - 5}{3 - (-1)} = \frac{-3}{4}

  1. Between (3,2)(3,2) and (4,1)(4,1):

m2=1243=11=1m_2 = \frac{1 - 2}{4 - 3} = \frac{-1}{1} = -1

  1. Between (4,1)(4,1) and (0,2)(0,-2):

m3=2104=34=34m_3 = \frac{-2 - 1}{0 - 4} = \frac{-3}{-4} = \frac{3}{4}

  1. Between (0,2)(0,-2) and (1,5)(-1,5):

m4=5(2)10=71=7m_4 = \frac{5 - (-2)}{-1 - 0} = \frac{7}{-1} = -7

Perpendicular Check:

  • m1×m2=34×(1)=34m_1 \times m_2 = \frac{-3}{4} \times (-1) = \frac{3}{4} (Not equal to 1-1)
  • m2×m3=1×34=34m_2 \times m_3 = -1 \times \frac{3}{4} = \frac{-3}{4} (Not equal to 1-1)
  • m3×m4=34×7=214m_3 \times m_4 = \frac{3}{4} \times -7 = \frac{-21}{4} (Not equal to 1-1)

None of the adjacent sides are perpendicular, so the angles are not 90 degrees.

Step 4: Check if Opposite Sides are Parallel

Two lines are parallel if their slopes are equal.

  • m1m_1 and m3m_3 (opposite sides): 34\frac{-3}{4} and 34\frac{3}{4} (Not equal, so not parallel).
  • m2m_2 and m4m_4 (opposite sides): 1-1 and 7-7 (Not equal, so not parallel).

Conclusion:

The given points do not form a square. The sides are not of equal length, the angles are not 90 degrees, and the opposite sides are not parallel.

Would you like more details or have any questions?


Follow-Up Questions:

  1. What conditions must be met for four points to form a rectangle?
  2. How do you determine if a quadrilateral is a parallelogram using its vertices?
  3. Can the given points form any other special quadrilateral, such as a rhombus or trapezoid?
  4. How can we verify if the given points are collinear?
  5. What is the role of the distance formula in coordinate geometry?

Tip:

In coordinate geometry, always verify the distances and angles when identifying shapes based on their vertices. This helps in accurately classifying the shapes.

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Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Geometric Shapes
Distance Formula
Slope of a Line
Perpendicular Lines
Parallel Lines

Formulas

Distance formula
Slope formula

Theorems

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Suitable Grade Level

High School