Math Problem Statement

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Calculate the determinant of the matrix: [[-5, -5, 0], [-3, 3, -5], [5, 6, -3]].

Solution

The matrix you provided is a 3x3 matrix:

-5 & -5 & 0 \\ -3 & 3 & -5 \\ 5 & 6 & -3 \end{pmatrix}$$ To calculate the determinant of this matrix, we can use the formula for a 3x3 determinant: $$\text{det}(A) = a(ei - fh) - b(di - fg) + c(dh - eg)$$ For matrix: $$A = \begin{pmatrix} a & b & c \\ d & e & f \\ g & h & i \end{pmatrix}$$ Substituting the values from the matrix: $$\text{det}(A) = (-5)((3)(-3) - (-5)(6)) - (-5)((-3)(-3) - (-5)(5)) + (0)((-3)(6) - (3)(5))$$ Simplifying step-by-step: $$= (-5)((-9) + 30) - (-5)((9) + 25) + 0$$ $$= (-5)(21) + 5(34)$$ $$= -105 + 170$$ $$= 65$$ Therefore, the determinant of the matrix is **65**. Would you like a further explanation or details? Here are some related questions you can explore: 1. How to calculate the determinant of a 2x2 matrix? 2. What are the properties of a determinant? 3. How does the determinant of a matrix affect its invertibility? 4. What does a zero determinant imply about a matrix? 5. Can a matrix with all elements zero still have a non-zero determinant? **Tip**: A matrix with a determinant of zero is called singular, which means it does not have an inverse.

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Determinants
3x3 Matrices

Formulas

det(A) = a(ei - fh) - b(di - fg) + c(dh - eg)

Theorems

Cofactor expansion of a 3x3 determinant

Suitable Grade Level

Grades 9-11