Math Problem Statement

find derivites of y = squareroot 5x + 2

Solution

To find the derivative of the function y=5x+2y = \sqrt{5x + 2}, we can apply the chain rule. Here's how:

Step-by-step solution:

  1. Rewrite the function in exponent form: y=(5x+2)1/2y = (5x + 2)^{1/2}

  2. Use the chain rule, which states that if y=[u(x)]ny = [u(x)]^n, then: dydx=n[u(x)]n1dudx\frac{dy}{dx} = n \cdot [u(x)]^{n-1} \cdot \frac{du}{dx} Here, u(x)=5x+2u(x) = 5x + 2 and n=12n = \frac{1}{2}.

  3. Differentiate:

    • First, apply the power rule: dydx=12(5x+2)1/2\frac{dy}{dx} = \frac{1}{2} \cdot (5x + 2)^{-1/2}
    • Now, multiply by the derivative of the inside function u(x)=5x+2u(x) = 5x + 2, which is dudx=5\frac{du}{dx} = 5.
  4. Combine: dydx=12(5x+2)1/25\frac{dy}{dx} = \frac{1}{2} \cdot (5x + 2)^{-1/2} \cdot 5

  5. Simplify: dydx=525x+2\frac{dy}{dx} = \frac{5}{2 \sqrt{5x + 2}}

Final derivative:

dydx=525x+2\frac{dy}{dx} = \frac{5}{2 \sqrt{5x + 2}}

Would you like more details or have any questions?

Related Questions:

  1. How do you apply the chain rule to more complex functions?
  2. What is the derivative of x2+3x\sqrt{x^2 + 3x}?
  3. Can you find the second derivative of y=5x+2y = \sqrt{5x + 2}?
  4. How do derivatives of square root functions differ from those of polynomials?
  5. How would you differentiate y=15x+2y = \frac{1}{\sqrt{5x + 2}}?

Tip:

When differentiating functions involving roots or powers, rewriting them in exponent form often makes the process much easier.

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Math Problem Analysis

Mathematical Concepts

Calculus
Derivatives
Chain Rule

Formulas

Chain rule: dy/dx = n * [u(x)]^(n-1) * du/dx
Power rule: dy/dx = n * x^(n-1)

Theorems

Chain Rule of Differentiation

Suitable Grade Level

Grades 11-12