Math Problem Statement

Given f(2) = 4 and f'(2) = 5, find the value of h'(2) based on the function h(x) = (f(x))^2.

Solution

To solve the problem, we need to find the derivative of h(x)=(f(x))2h(x) = (f(x))^2 and then evaluate it at x=2x = 2.

Step 1: Differentiate h(x)h(x)

The function h(x)=(f(x))2h(x) = (f(x))^2 is a composition of functions, so we need to apply the chain rule to differentiate it:

h(x)=2f(x)f(x)h'(x) = 2f(x) \cdot f'(x)

Step 2: Substitute the given values

Now, we substitute x=2x = 2, f(2)=4f(2) = 4, and f(2)=5f'(2) = 5:

h(2)=2f(2)f(2)h'(2) = 2 \cdot f(2) \cdot f'(2)

Substitute the given values:

h(2)=245h'(2) = 2 \cdot 4 \cdot 5

Step 3: Calculate the value

h(2)=220=40h'(2) = 2 \cdot 20 = 40

Final Answer

The value of h(2)h'(2) is 40.

Would you like more details, or do you have any questions?

Related Questions

  1. What is the chain rule in calculus, and how is it applied to functions?
  2. How do you find the derivative of a composite function?
  3. What is the significance of the derivative at a specific point?
  4. Can you solve for h(x)h'(x) if h(x)=f(x)g(x)h(x) = f(x)g(x) and both f(x)f(x) and g(x)g(x) are given?
  5. How does the product rule differ from the chain rule?

Tip

When differentiating a function that involves another function raised to a power, remember to use the chain rule by differentiating the outer function first and then multiplying by the derivative of the inner function.

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Math Problem Analysis

Mathematical Concepts

Calculus
Derivatives
Chain Rule

Formulas

h'(x) = 2 * f(x) * f'(x)

Theorems

Chain Rule

Suitable Grade Level

Grade 12 or College-level Calculus