Math Problem Statement

مشتق هذه الدالة عند-1

Solution

The function provided in the image is:

f(x)=(x+1)+3x2f(x) = -(x + 1) + \frac{3}{x - 2}

To find the derivative of this function, f(x)f'(x), and then evaluate it at x=1x = -1, we follow these steps:

Step 1: Differentiate f(x)f(x)

  1. Differentiate (x+1)-(x + 1): ddx[(x+1)]=1\frac{d}{dx}[-(x + 1)] = -1
  2. Differentiate 3x2\frac{3}{x - 2} using the chain rule: ddx(3x2)=3ddx(1x2)\frac{d}{dx}\left(\frac{3}{x - 2}\right) = 3 \cdot \frac{d}{dx}\left(\frac{1}{x - 2}\right) The derivative of 1x2\frac{1}{x - 2} is: ddx(1x2)=1(x2)2\frac{d}{dx}\left(\frac{1}{x - 2}\right) = -\frac{1}{(x - 2)^2} Therefore, ddx(3x2)=3(x2)2\frac{d}{dx}\left(\frac{3}{x - 2}\right) = -\frac{3}{(x - 2)^2}

So, the derivative f(x)f'(x) is: f(x)=13(x2)2f'(x) = -1 - \frac{3}{(x - 2)^2}

Step 2: Evaluate f(x)f'(x) at x=1x = -1

f(1)=13(12)2=13(3)2=139=113=43f'(-1) = -1 - \frac{3}{(-1 - 2)^2} = -1 - \frac{3}{(-3)^2} = -1 - \frac{3}{9} = -1 - \frac{1}{3} = -\frac{4}{3}

Thus, the derivative of the function at x=1x = -1 is f(1)=43f'(-1) = -\frac{4}{3}.

Would you like more details on this process, or do you have any other questions?

Related Questions:

  1. How do you apply the chain rule in differentiation?
  2. What is the significance of the derivative of a function?
  3. How do you find the critical points of a function?
  4. What are the steps to differentiate rational functions?
  5. How do you interpret the derivative in real-world applications?

Tip:

Always remember to simplify the function as much as possible before differentiating. This can often make the differentiation process easier.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Differentiation
Chain Rule
Rational Functions

Formulas

Derivative formulas

Theorems

-

Suitable Grade Level

College Level